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31: 4.38 Inverse Hyperbolic Functions: Further Properties
4.38.15 Arcsinh u ± Arcsinh v = Arcsinh ( u ( 1 + v 2 ) 1 / 2 ± v ( 1 + u 2 ) 1 / 2 ) ,
4.38.16 Arccosh u ± Arccosh v = Arccosh ( u v ± ( ( u 2 1 ) ( v 2 1 ) ) 1 / 2 ) ,
4.38.17 Arctanh u ± Arctanh v = Arctanh ( u ± v 1 ± u v ) ,
4.38.18 Arcsinh u ± Arccosh v = Arcsinh ( u v ± ( ( 1 + u 2 ) ( v 2 1 ) ) 1 / 2 ) = Arccosh ( v ( 1 + u 2 ) 1 / 2 ± u ( v 2 1 ) 1 / 2 ) ,
4.38.19 Arctanh u ± Arccoth v = Arctanh ( u v ± 1 v ± u ) = Arccoth ( v ± u u v ± 1 ) .
32: 10.73 Physical Applications
See Jackson (1999, Chapter 3, §§3.7, 3.8, 3.11, 3.13), Lamb (1932, Chapter V, §§100–102; Chapter VIII, §§186, 191–193; Chapter X, §§303, 304), Happel and Brenner (1973, Chapter 3, §3.3; Chapter 7, §7.3), Korenev (2002, Chapter 4, §43), and Gray et al. (1922, Chapter XI). …and on separation of variables we obtain solutions of the form e ± i n ϕ e ± κ z J n ( κ r ) , from which a solution satisfying prescribed boundary conditions may be constructed. … on assuming a time dependence of the form e ± i k t . …
33: 7.5 Interrelations
7.5.6 e ± 1 2 π i z 2 ( g ( z ) ± i f ( z ) ) = 1 2 ( 1 ± i ) ( C ( z ) ± i S ( z ) ) .
7.5.7 ζ = 1 2 π ( 1 i ) z ,
7.5.8 C ( z ) ± i S ( z ) = 1 2 ( 1 ± i ) erf ζ .
7.5.9 C ( z ) ± i S ( z ) = 1 2 ( 1 ± i ) ( 1 e ± 1 2 π i z 2 w ( i ζ ) ) .
7.5.10 g ( z ) ± i f ( z ) = 1 2 ( 1 ± i ) e ζ 2 erfc ζ .
34: 28.17 Stability as x ±
§28.17 Stability as x ±
If all solutions of (28.2.1) are bounded when x ± along the real axis, then the corresponding pair of parameters ( a , q ) is called stable. …
35: 12.2 Differential Equations
Standard solutions are U ( a , ± z ) , V ( a , ± z ) , U ¯ ( a , ± x ) (not complex conjugate), U ( a , ± i z ) for (12.2.2); W ( a , ± x ) for (12.2.3); D ν ( ± z ) for (12.2.4), where … The solutions W ( a , ± x ) are treated in §12.14. …
12.2.12 𝒲 { U ( a , z ) , U ( a , ± i z ) } = i e ± i π ( 1 2 a + 1 4 ) .
12.2.18 2 π U ( a , z ) = Γ ( 1 2 a ) ( e i π ( 1 2 a + 1 4 ) U ( a , ± i z ) + e ± i π ( 1 2 a + 1 4 ) U ( a , i z ) ) ,
12.2.19 U ( a , z ) = ± i e ± i π a U ( a , z ) + 2 π Γ ( 1 2 + a ) e ± i π ( 1 2 a 1 4 ) U ( a , ± i z ) .
36: 32.10 Special Function Solutions
For example, if α = 1 2 ε , with ε = ± 1 , then the Riccati equation is … Solutions for other values of α are derived from w ( z ; ± 1 2 ) by application of the Bäcklund transformations (32.7.1) and (32.7.2). … with n , and ε 1 = ± 1 , ε 2 = ± 1 , independently. … with n and ε = ± 1 . In the case when n = 0 in (32.10.15), the Riccati equation is …
37: 10.13 Other Differential Equations
10.13.4 w ′′ + 1 2 ν z w + λ 2 w = 0 , w = z ± ν 𝒞 ν ( λ z ) ,
See also Watson (1944, pp. 95–100).
38: 19.22 Quadratic Transformations
19.22.5 2 p ± = ( p + x ) ( p + y ) ± ( p x ) ( p y ) ,
4 ( p ± 2 a 2 ) = ( p 2 x 2 ± p 2 y 2 ) 2 .
2 z ± = ( z + x ) ( z + y ) ± ( z x ) ( z y ) ,
4 ( z ± 2 a 2 ) = ( z 2 x 2 ± z 2 y 2 ) 2 .
However, if x and y are complex conjugates and z and p are real, then the right-hand sides of all transformations in §§19.22(i) and 19.22(iii)—except (19.22.3) and (19.22.22)—are free of complex numbers and p ± 2 p 2 = ± | p 2 x 2 | 0 . …
39: Errata
  • Equation (33.11.1)
    33.11.1 H ± ( η , ρ ) = e ± i θ ( η , ρ ) k = 0 ( a ) k ( b ) k k ! ( ± 2 i ρ ) k

    Originally the factor in the denominator on the right-hand side was written incorrectly as ( 2 i ρ ) k . This has been corrected to ( ± 2 i ρ ) k .

    Reported by Ian Thompson on 2018-05-17

  • Equation (8.12.18)
    8.12.18 Q ( a , z ) P ( a , z ) } z a 1 2 e z Γ ( a ) ( d ( ± χ ) k = 0 A k ( χ ) z k / 2 k = 1 B k ( χ ) z k / 2 )

    The original ± in front of the second summation was replaced by to correct an error in Paris (2002b); for details see https://arxiv.org/abs/1611.00548.

    Reported 2017-01-28 by Richard Paris.

  • Equation (8.12.5)

    To be consistent with the notation used in (8.12.16), Equation (8.12.5) was changed to read

    8.12.5 e ± π i a 2 i sin ( π a ) Q ( a , z e ± π i ) = ± 1 2 erfc ( ± i η a / 2 ) i T ( a , η )
  • Table 3.5.21

    The correct corner coordinates for the 9-point square, given on the last line of this table, are ( ± 3 5 h , ± 3 5 h ) . Originally they were given incorrectly as ( ± 3 5 h , 0 ) , ( ± 3 5 h , 0 ) .

    Diagram ( x j , y j ) w j R
    \begin{picture}(2.4,3.0)(-1.2,-1.55)\put(0.0,0.0){\line(1,0){0.05}}\put(0.1,0.% 0){\line(1,0){0.05}}\put(0.2,0.0){\line(1,0){0.05}}\put(0.3,0.0){\line(1,0){0.% 05}}\put(0.4,0.0){\line(1,0){0.05}}\put(0.5,0.0){\line(1,0){0.05}}\put(0.6,0.0% ){\line(1,0){0.05}}\put(0.7,0.0){\line(1,0){0.05}}\put(0.8,0.0){\line(1,0){0.0% 5}}\put(0.9,0.0){\line(1,0){0.05}} \put(0.0,0.0){\line(0,1){0.05}}\put(0.0,0.1){\line(0,1){0.05}}\put(0.0,0.2){% \line(0,1){0.05}}\put(0.0,0.3){\line(0,1){0.05}}\put(0.0,0.4){\line(0,1){0.05}% }\put(0.0,0.5){\line(0,1){0.05}}\put(0.0,0.6){\line(0,1){0.05}}\put(0.0,0.7){% \line(0,1){0.05}}\put(0.0,0.8){\line(0,1){0.05}}\put(0.0,0.9){\line(0,1){0.05}% } \put(0.0,0.0){\line(-1,0){0.05}}\put(-0.1,0.0){\line(-1,0){0.05}}\put(-0.2,0.0% ){\line(-1,0){0.05}}\put(-0.3,0.0){\line(-1,0){0.05}}\put(-0.4,0.0){\line(-1,0% ){0.05}}\put(-0.5,0.0){\line(-1,0){0.05}}\put(-0.6,0.0){\line(-1,0){0.05}}\put% (-0.7,0.0){\line(-1,0){0.05}}\put(-0.8,0.0){\line(-1,0){0.05}}\put(-0.9,0.0){% \line(-1,0){0.05}} \put(0.0,0.0){\line(0,-1){0.05}}\put(0.0,-0.1){\line(0,-1){0.05}}\put(0.0,-0.2% ){\line(0,-1){0.05}}\put(0.0,-0.3){\line(0,-1){0.05}}\put(0.0,-0.4){\line(0,-1% ){0.05}}\put(0.0,-0.5){\line(0,-1){0.05}}\put(0.0,-0.6){\line(0,-1){0.05}}\put% (0.0,-0.7){\line(0,-1){0.05}}\put(0.0,-0.8){\line(0,-1){0.05}}\put(0.0,-0.9){% \line(0,-1){0.05}} \put(-1.0,1.0){\line(1,0){2.0}} \put(-1.0,1.0){\line(0,-1){2.0}} \put(1.0,-1.0){\line(-1,0){2.0}} \put(1.0,-1.0){\line(0,1){2.0}} \put(0.0,0.0){\circle*{0.15}}\put(0.7746,0.0){\circle*{0.15}}\put(-0.7746,0.0)% {\circle*{0.15}}\put(0.0,0.7746){\circle*{0.15}}\put(0.0,-0.7746){\circle*{0.1% 5}}\put(0.7746,0.7746){\circle*{0.15}}\put(-0.7746,0.7746){\circle*{0.15}}\put% (0.7746,-0.7746){\circle*{0.15}}\put(-0.7746,-0.7746){\circle*{0.15}}\end{picture}
    ( 0 , 0 ) 16 81 O ( h 6 )
    ( ± 3 5 h , 0 ) , ( 0 , ± 3 5 h ) 10 81
    ( ± 3 5 h , ± 3 5 h ) 25 324

    Reported 2014-01-13 by Stanley Oleszczuk.

  • Equation (4.21.1)
    4.21.1 sin u ± cos u = 2 sin ( u ± 1 4 π ) = ± 2 cos ( u 1 4 π )

    Originally the symbol ± was missing after the second equal sign.

    Reported 2012-09-27 by Dennis Heim.

  • 40: 10.38 Derivatives with Respect to Order
    10.38.1 I ± ν ( z ) ν = ± I ± ν ( z ) ln ( 1 2 z ) ( 1 2 z ) ± ν k = 0 ψ ( k + 1 ± ν ) Γ ( k + 1 ± ν ) ( 1 4 z 2 ) k k ! ,
    10.38.6 I ν ( x ) ν | ν = ± 1 2 = 1 2 π x ( E 1 ( 2 x ) e x ± Ei ( 2 x ) e x ) ,