About the Project

negative%20definite

AdvancedHelp

(0.001 seconds)

11—20 of 211 matching pages

11: 9.18 Tables
  • Fox (1960, Table 3) tabulates 2 π 1 / 2 x 1 / 4 exp ( 2 3 x 3 / 2 ) Ai ( x ) , 2 π 1 / 2 x 1 / 4 exp ( 2 3 x 3 / 2 ) Ai ( x ) , π 1 / 2 x 1 / 4 exp ( 2 3 x 3 / 2 ) Bi ( x ) , and π 1 / 2 x 1 / 4 exp ( 2 3 x 3 / 2 ) Bi ( x ) for 3 2 x 3 / 2 = 0 ( .001 ) 0.05 , together with similar auxiliary functions for negative values of x . Precision is 10D.

  • Zhang and Jin (1996, p. 337) tabulates Ai ( x ) , Ai ( x ) , Bi ( x ) , Bi ( x ) for x = 0 ( 1 ) 20 to 8S and for x = 20 ( 1 ) 0 to 9D.

  • Miller (1946) tabulates a k , Ai ( a k ) , a k , Ai ( a k ) , k = 1 ( 1 ) 50 ; b k , Bi ( b k ) , b k , Bi ( b k ) , k = 1 ( 1 ) 20 . Precision is 8D. Entries for k = 1 ( 1 ) 20 are reproduced in Abramowitz and Stegun (1964, Chapter 10).

  • Sherry (1959) tabulates a k , Ai ( a k ) , a k , Ai ( a k ) , k = 1 ( 1 ) 50 ; 20S.

  • Gil et al. (2003c) tabulates the only positive zero of Gi ( z ) , the first 10 negative real zeros of Gi ( z ) and Gi ( z ) , and the first 10 complex zeros of Gi ( z ) , Gi ( z ) , Hi ( z ) , and Hi ( z ) . Precision is 11 or 12S.

  • 12: Bibliography T
  • I. C. Tang (1969) Some definite integrals and Fourier series for Jacobian elliptic functions. Z. Angew. Math. Mech. 49, pp. 95–96.
  • N. M. Temme (1996a) Uniform asymptotics for the incomplete gamma functions starting from negative values of the parameters. Methods Appl. Anal. 3 (3), pp. 335–344.
  • I. Thompson (2013) Algorithm 926: incomplete gamma functions with negative arguments. ACM Trans. Math. Software 39 (2), pp. Art. 14, 9.
  • 13: 25.11 Hurwitz Zeta Function
    See accompanying text
    Figure 25.11.1: Hurwitz zeta function ζ ( x , a ) , a = 0. …8, 1, 20 x 10 . … Magnify
    25.11.30 ζ ( s , a ) = Γ ( 1 s ) 2 π i ( 0 + ) e a z z s 1 1 e z d z , s 1 , a > 0 ,
    where the integration contour is a loop around the negative real axis as described for (25.5.20). …
    25.11.32 0 a x n ψ ( x ) d x = ( 1 ) n 1 ζ ( n ) + ( 1 ) n H n B n + 1 n + 1 k = 0 n ( 1 ) k ( n k ) H k B k + 1 ( a ) k + 1 a n k + k = 0 n ( 1 ) k ( n k ) ζ ( k , a ) a n k , n = 1 , 2 , , a > 0 ,
    25.11.34 n 0 a ζ ( 1 n , x ) d x = ζ ( n , a ) ζ ( n ) + B n + 1 B n + 1 ( a ) n ( n + 1 ) , n = 1 , 2 , , a > 0 .
    14: 34.3 Basic Properties: 3 j Symbol
    34.3.1 ( j j 0 m m 0 ) = ( 1 ) j m ( 2 j + 1 ) 1 2 ,
    34.3.2 ( j j 1 m m 0 ) = ( 1 ) j m 2 m ( 2 j ( 2 j + 1 ) ( 2 j + 2 ) ) 1 2 , j 1 2 ,
    34.3.3 ( j j 1 m m 1 1 ) = ( 1 ) j m ( 2 ( j m ) ( j + m + 1 ) 2 j ( 2 j + 1 ) ( 2 j + 2 ) ) 1 2 , j 1 2 .
    34.3.4 J = j 1 + j 2 + j 3 .
    34.3.8 ( j 1 j 2 j 3 m 1 m 2 m 3 ) = ( j 2 j 3 j 1 m 2 m 3 m 1 ) = ( j 3 j 1 j 2 m 3 m 1 m 2 ) ,
    15: 34.1 Special Notation
    2 j 1 , 2 j 2 , 2 j 3 , 2 l 1 , 2 l 2 , 2 l 3 nonnegative integers.
    34.1.1 ( j 1 m 1 j 2 m 2 | j 1 j 2 j 3 m 3 ) = ( 1 ) j 1 j 2 + m 3 ( 2 j 3 + 1 ) 1 2 ( j 1 j 2 j 3 m 1 m 2 m 3 ) ;
    16: 25.12 Polylogarithms
    25.12.2 Li 2 ( z ) = 0 z t 1 ln ( 1 t ) d t , z ( 1 , ) .
    25.12.9 n = 1 sin ( n θ ) n 2 = 0 θ ln ( 2 sin ( 1 2 x ) ) d x .
    See accompanying text
    Figure 25.12.1: Dilogarithm function Li 2 ( x ) , 20 x < 1 . Magnify
    See accompanying text
    Figure 25.12.2: Absolute value of the dilogarithm function | Li 2 ( x + i y ) | , 20 x 20 , 20 y 20 . … Magnify 3D Help
    17: 1.5 Calculus of Two or More Variables
    and the second order term in (1.5.18) is positive definite (negative definite), that is, …
    18: 1.11 Zeros of Polynomials
    A monic polynomial of even degree with real coefficients has at least two zeros of opposite signs when the constant term is negative. … A similar relation holds for the changes in sign of the coefficients of f ( z ) , and hence for the number of negative zeros of f ( z ) . … Both polynomials have one change of sign; hence for each polynomial there is one positive zero, one negative zero, and six complex zeros. … Resolvent cubic is z 3 + 12 z 2 + 20 z + 9 = 0 with roots θ 1 = 1 , θ 2 = 1 2 ( 11 + 85 ) , θ 3 = 1 2 ( 11 85 ) , and θ 1 = 1 , θ 2 = 1 2 ( 17 + 5 ) , θ 3 = 1 2 ( 17 5 ) . … with real coefficients, is called stable if the real parts of all the zeros are strictly negative. …
    19: 34.2 Definition: 3 j Symbol
    34.2.1 | j r j s | j t j r + j s ,
    34.2.2 m r = j r , j r + 1 , , j r 1 , j r , r = 1 , 2 , 3 ,
    34.2.4 ( j 1 j 2 j 3 m 1 m 2 m 3 ) = ( 1 ) j 1 j 2 m 3 Δ ( j 1 j 2 j 3 ) ( ( j 1 + m 1 ) ! ( j 1 m 1 ) ! ( j 2 + m 2 ) ! ( j 2 m 2 ) ! ( j 3 + m 3 ) ! ( j 3 m 3 ) ! ) 1 2 s ( 1 ) s s ! ( j 1 + j 2 j 3 s ) ! ( j 1 m 1 s ) ! ( j 2 + m 2 s ) ! ( j 3 j 2 + m 1 + s ) ! ( j 3 j 1 m 2 + s ) ! ,
    34.2.5 Δ ( j 1 j 2 j 3 ) = ( ( j 1 + j 2 j 3 ) ! ( j 1 j 2 + j 3 ) ! ( j 1 + j 2 + j 3 ) ! ( j 1 + j 2 + j 3 + 1 ) ! ) 1 2 ,
    34.2.6 ( j 1 j 2 j 3 m 1 m 2 m 3 ) = ( 1 ) j 2 m 1 + m 3 ( j 1 + j 2 + m 3 ) ! ( j 2 + j 3 m 1 ) ! Δ ( j 1 j 2 j 3 ) ( j 1 + j 2 + j 3 + 1 ) ! ( ( j 1 + m 1 ) ! ( j 3 m 3 ) ! ( j 1 m 1 ) ! ( j 2 + m 2 ) ! ( j 2 m 2 ) ! ( j 3 + m 3 ) ! ) 1 2 F 2 3 ( j 1 j 2 j 3 1 , j 1 + m 1 , j 3 m 3 ; j 1 j 2 m 3 , j 2 j 3 + m 1 ; 1 ) ,
    20: 34.4 Definition: 6 j Symbol
    34.4.1 { j 1 j 2 j 3 l 1 l 2 l 3 } = m r m s ( 1 ) l 1 + m 1 + l 2 + m 2 + l 3 + m 3 ( j 1 j 2 j 3 m 1 m 2 m 3 ) ( j 1 l 2 l 3 m 1 m 2 m 3 ) ( l 1 j 2 l 3 m 1 m 2 m 3 ) ( l 1 l 2 j 3 m 1 m 2 m 3 ) ,
    34.4.2 { j 1 j 2 j 3 l 1 l 2 l 3 } = Δ ( j 1 j 2 j 3 ) Δ ( j 1 l 2 l 3 ) Δ ( l 1 j 2 l 3 ) Δ ( l 1 l 2 j 3 ) s ( 1 ) s ( s + 1 ) ! ( s j 1 j 2 j 3 ) ! ( s j 1 l 2 l 3 ) ! ( s l 1 j 2 l 3 ) ! ( s l 1 l 2 j 3 ) ! 1 ( j 1 + j 2 + l 1 + l 2 s ) ! ( j 2 + j 3 + l 2 + l 3 s ) ! ( j 3 + j 1 + l 3 + l 1 s ) ! ,
    34.4.3 { j 1 j 2 j 3 l 1 l 2 l 3 } = ( 1 ) j 1 + j 3 + l 1 + l 3 Δ ( j 1 j 2 j 3 ) Δ ( j 2 l 1 l 3 ) ( j 1 j 2 + l 1 + l 2 ) ! ( j 2 + j 3 + l 2 + l 3 ) ! ( j 1 + j 3 + l 1 + l 3 + 1 ) ! Δ ( j 1 l 2 l 3 ) Δ ( j 3 l 1 l 2 ) ( j 1 j 2 + j 3 ) ! ( j 2 + l 1 + l 3 ) ! ( j 1 + l 2 + l 3 + 1 ) ! ( j 3 + l 1 + l 2 + 1 ) ! F 3 4 ( j 1 + j 2 j 3 , j 2 l 1 l 3 , j 1 l 2 l 3 1 , j 3 l 1 l 2 1 j 1 + j 2 l 1 l 2 , j 2 j 3 l 2 l 3 , j 1 j 3 l 1 l 3 1 ; 1 ) ,