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21: 13.29 Methods of Computation
A comprehensive and powerful approach is to integrate the differential equations (13.2.1) and (13.14.1) by direct numerical methods. As described in §3.7(ii), to insure stability the integration path must be chosen in such a way that as we proceed along it the wanted solution grows in magnitude at least as fast as all other solutions of the differential equation. For M ( a , b , z ) and M κ , μ ( z ) this means that in the sector | ph z | π we may integrate along outward rays from the origin with initial values obtained from (13.2.2) and (13.14.2). … In the sector | ph z | < 1 2 π the integration has to be towards the origin, with starting values computed from asymptotic expansions (§§13.7 and 13.19). On the rays ph z = ± 1 2 π , integration can proceed in either direction. …
22: 28.8 Asymptotic Expansions for Large q
28.8.6 C ^ m ( π h 2 ( m ! ) 2 ) 1 / 4 ( 1 + 2 m + 1 8 h + m 4 + 2 m 3 + 263 m 2 + 262 m + 108 2048 h 2 + ) 1 / 2 ,
28.8.7 S ^ m ( π h 2 ( m ! ) 2 ) 1 / 4 ( 1 2 m + 1 8 h + m 4 + 2 m 3 121 m 2 122 m 84 2048 h 2 + ) 1 / 2 .
28.8.9 W m ± ( x ) = e ± 2 h sin x ( cos x ) m + 1 { ( cos ( 1 2 x + 1 4 π ) ) 2 m + 1 , ( sin ( 1 2 x + 1 4 π ) ) 2 m + 1 ,
28.8.11 P m ( x ) 1 + s 2 3 h cos 2 x + 1 h 2 ( s 4 + 86 s 2 + 105 2 11 cos 4 x s 4 + 22 s 2 + 57 2 11 cos 2 x ) + ,
28.8.12 Q m ( x ) sin x cos 2 x ( 1 2 5 h ( s 2 + 3 ) + 1 2 9 h 2 ( s 3 + 3 s + 4 s 3 + 44 s cos 2 x ) ) + .
23: 2.3 Integrals of a Real Variable
§2.3(i) Integration by Parts
Then the series obtained by substituting (2.3.7) into (2.3.1) and integrating formally term by term yields an asymptotic expansion: … derives from the neighborhood of the minimum of p ( t ) in the integration range. … A uniform approximation can be constructed by quadratic change of integration variable: … We replace the limit κ by and integrate term-by-term: …
24: 12.10 Uniform Asymptotic Expansions for Large Parameter
12.10.8 𝒜 s ( t ) = u s ( t ) ( t 2 1 ) 3 2 s , s ( t ) = v s ( t ) ( t 2 1 ) 3 2 s ,
12.10.23 η = 1 2 arccos t 1 2 t 1 t 2 ,
12.10.32 τ = 1 2 ( t t 2 1 1 ) ,
12.10.33 𝖠 s + 1 ( τ ) = 4 τ 2 ( τ + 1 ) 2 d d τ 𝖠 s ( τ ) 1 4 0 τ ( 20 u 2 + 20 u + 3 ) 𝖠 s ( u ) d u , s = 0 , 1 , 2 , ,
12.10.40 ϕ ( ζ ) = ( ζ t 2 1 ) 1 4 .
25: 36.12 Uniform Approximation of Integrals
In the cuspoid case (one integration variable)
36.12.1 I ( 𝐲 , k ) = exp ( i k f ( u ; 𝐲 ) ) g ( u , 𝐲 ) d u ,
36.12.4 f ( u ( t , 𝐲 ) ; 𝐲 ) = A ( 𝐲 ) + Φ K ( t ; 𝐱 ( 𝐲 ) ) ,
36.12.6 A ( 𝐲 ) = f ( u ( 0 , 𝐲 ) ; 𝐲 ) ,
36.12.8 a m ( 𝐲 ) = n = 1 K + 1 P m n ( 𝐲 ) G n ( 𝐲 ) ( t n ( 𝐱 ( 𝐲 ) ) ) m + 1 l = 1 l n K + 1 ( t n ( 𝐱 ( 𝐲 ) ) t l ( 𝐱 ( 𝐲 ) ) ) ,
26: 31.5 Solutions Analytic at Three Singularities: Heun Polynomials
31.5.2 𝐻𝑝 n , m ( a , q n , m ; n , β , γ , δ ; z ) = H ( a , q n , m ; n , β , γ , δ ; z )
27: 19.13 Integrals of Elliptic Integrals
§19.13(i) Integration with Respect to the Modulus
§19.13(ii) Integration with Respect to the Amplitude
28: 1.8 Fourier Series
where f ( x ) is square-integrable on [ π , π ] and a n , b n , c n are given by (1.8.2), (1.8.4). If g ( x ) is also square-integrable with Fourier coefficients a n , b n or c n then … Let f ( x ) be an absolutely integrable function of period 2 π , and continuous except at a finite number of points in any bounded interval. …
§1.8(iii) Integration and Differentiation
Suppose that f ( x ) is twice continuously differentiable and f ( x ) and | f ′′ ( x ) | are integrable over ( , ) . …
29: 3.11 Approximation Techniques
3.11.3 m j = ( 1 ) j ϵ n ( x j ) , j = 0 , 1 , , n + 1 .
The iterative process converges locally and quadratically (§3.8(i)). … They enjoy an orthogonal property with respect to integrals: …
3.11.16 R k , ( x ) = p 0 + p 1 x + + p k x k 1 + q 1 x + + q x
3.11.20 f ( z ) = c 0 + c 1 z + c 2 z 2 +
30: 1.11 Zeros of Polynomials
1.11.9 D = a n 2 n 2 j < k ( z j z k ) 2 ,
1.11.12 D = 4 p 3 27 q 2 .
1.11.17 D = 16 p 4 r 4 p 3 q 2 128 p 2 r 2 + 144 p q 2 r 27 q 4 + 256 r 3 .
Resolvent cubic is z 3 + 12 z 2 + 20 z + 9 = 0 with roots θ 1 = 1 , θ 2 = 1 2 ( 11 + 85 ) , θ 3 = 1 2 ( 11 85 ) , and θ 1 = 1 , θ 2 = 1 2 ( 17 + 5 ) , θ 3 = 1 2 ( 17 5 ) . …