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41: 5.9 Integral Representations
5.9.10 Ln Γ ( z ) = ( z 1 2 ) ln z z + 1 2 ln ( 2 π ) + 2 0 arctan ( t / z ) e 2 π t 1 d t ,
42: 9.1 Special Notation
Other notations that have been used are as follows: Ai ( x ) and Bi ( x ) for Ai ( x ) and Bi ( x ) (Jeffreys (1928), later changed to Ai ( x ) and Bi ( x ) ); U ( x ) = π Bi ( x ) , V ( x ) = π Ai ( x ) (Fock (1945)); A ( x ) = 3 1 / 3 π Ai ( 3 1 / 3 x ) (Szegő (1967, §1.81)); e 0 ( x ) = π Hi ( x ) , e ~ 0 ( x ) = π Gi ( x ) (Tumarkin (1959)).
43: 5.11 Asymptotic Expansions
5.11.1 Ln Γ ( z ) ( z 1 2 ) ln z z + 1 2 ln ( 2 π ) + k = 1 B 2 k 2 k ( 2 k 1 ) z 2 k 1
5.11.3 Γ ( z ) = e z z z ( 2 π z ) 1 / 2 Γ ( z ) e z z z ( 2 π z ) 1 / 2 k = 0 g k z k ,
5.11.7 Γ ( a z + b ) 2 π e a z ( a z ) a z + b ( 1 / 2 ) ,
5.11.8 Ln Γ ( z + h ) ( z + h 1 2 ) ln z z + 1 2 ln ( 2 π ) + k = 2 ( 1 ) k B k ( h ) k ( k 1 ) z k 1 ,
5.11.9 | Γ ( x + i y ) | 2 π | y | x ( 1 / 2 ) e π | y | / 2 ,
44: 8.11 Asymptotic Approximations and Expansions
If a is real and z ( = x ) is positive, then R n ( a , x ) is bounded in absolute value by the first neglected term u n / x n and has the same sign provided that n a 1 . …
§8.11(iii) Large a , Fixed z / a
§8.11(iv) Large a , Bounded ( x a ) / ( 2 a ) 1 2
If x = a + ( 2 a ) 1 2 y and a + , then … With x = 1 , an asymptotic expansion of e n ( n x ) / e n x follows from (8.11.14) and (8.11.16). …
45: 11.11 Asymptotic Expansions of Anger–Weber Functions
§11.11(iii) Large ν , Fixed z / ν
b 0 ( λ ) = 1 ( 1 λ 2 ) 1 / 4 ,
b 1 ( λ ) = 2 + 3 λ 2 12 ( 1 λ 2 ) 7 / 4 ,
b 2 ( λ ) = 4 + 300 λ 2 + 81 λ 4 864 ( 1 λ 2 ) 13 / 4 .
(Note that Olver’s definition of 𝐀 ν ( z ) omits the factor 1 / π in (11.10.4).) …
46: 3.11 Approximation Techniques
A sufficient condition for p n ( x ) to be the minimax polynomial is that | ϵ n ( x ) | attains its maximum at n + 2 distinct points in [ a , b ] and ϵ n ( x ) changes sign at these consecutive maxima. … where x = cos ( π / n ) and the double prime means that the first and last terms are to be halved. … It is denoted by [ p / q ] f ( z ) . … Starting with the first column [ n / 0 ] f , n = 0 , 1 , 2 , , and initializing the preceding column by [ n / 1 ] f = , n = 1 , 2 , , we can compute the lower triangular part of the table via (3.11.25). Similarly, the upper triangular part follows from the first row [ 0 / n ] f , n = 0 , 1 , 2 , , by initializing [ 1 / n ] f = 0 , n = 1 , 2 , . …
47: 1.11 Zeros of Polynomials
The number of positive zeros of a polynomial with real coefficients cannot exceed the number of times the coefficients change sign, and the two numbers have same parity. A similar relation holds for the changes in sign of the coefficients of f ( z ) , and hence for the number of negative zeros of f ( z ) . … Both polynomials have one change of sign; hence for each polynomial there is one positive zero, one negative zero, and six complex zeros. … The sum and product of the roots are respectively b / a and c / a . … are 1 , e 2 π i / n , e 4 π i / n , , e ( 2 n 2 ) π i / n , and of z n + 1 = 0 they are e π i / n , e 3 π i / n , , e ( 2 n 1 ) π i / n . …
48: 1.5 Calculus of Two or More Variables
The function f ( x , y ) is continuously differentiable if f , f / x , and f / y are continuous, and twice-continuously differentiable if also 2 f / x 2 , 2 f / y 2 , 2 f / x y , and 2 f / y x are continuous. … where f and its partial derivatives on the right-hand side are evaluated at ( a , b ) , and R n / ( λ 2 + μ 2 ) n / 2 0 as ( λ , μ ) ( 0 , 0 ) . …
Change of Order of Integration
§1.5(vi) Jacobians and Change of Variables
Change of Variables
49: 3.8 Nonlinear Equations
For multiple zeros the convergence is linear, but if the multiplicity m is known then quadratic convergence can be restored by multiplying the ratio f ( z n ) / f ( z n ) in (3.8.4) by m . …
  • (a)

    f ( x 0 ) f ′′ ( x 0 ) > 0 and f ( x ) , f ′′ ( x ) do not change sign between x 0 and ξ (monotonic convergence).

  • (b)

    f ( x 0 ) f ′′ ( x 0 ) < 0 , f ( x ) , f ′′ ( x ) do not change sign in the interval ( x 0 , x 1 ) , and ξ [ x 0 , x 1 ] (monotonic convergence after the first iteration).

  • 3.8.12 z n + 1 = z n f ( z n ) f ( z n ) ( f ′′ ( z n ) f ( z n ) / ( 2 f ( z n ) ) ) .
    Then the sensitivity of a simple zero z to changes in α is given by …
    50: 19.30 Lengths of Plane Curves
    19.30.2 s = a 0 ϕ 1 k 2 sin 2 θ d θ .
    k 2 = 1 ( b 2 / a 2 ) ,
    As λ increases, the eccentricity k decreases and the rate of change of arclength for a fixed value of ϕ is given by
    19.30.6 s ( 1 / k ) = a 2 b 2 F ( ϕ , k ) = a 2 b 2 R F ( c 1 , c k 2 , c ) , k 2 = ( a 2 b 2 ) / ( a 2 + λ ) , c = csc 2 ϕ .