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complementary exponential integral

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31: 7.13 Zeros
§7.13(ii) Zeros of erfc z
The other zeros of erfc z are z ¯ n . … In consequence of (7.5.5) and (7.5.10), zeros of ( z ) are related to zeros of erfc z . Thus if z n is a zero of erfc z 7.13(ii)), then ( 1 + i ) z n / π is a zero of ( z ) . For an asymptotic expansion of the zeros of 0 z exp ( 1 2 π i t 2 ) d t ( = ( 0 ) ( z ) = C ( z ) + i S ( z ) ) see Tuẑilin (1971). …
32: 8.12 Uniform Asymptotic Expansions for Large Parameter
8.12.5 e ± π i a 2 i sin ( π a ) Q ( a , z e ± π i ) = ± 1 2 erfc ( ± i η a / 2 ) i T ( a , η ) ,
where F ( x ) is Dawson’s integral; see §7.2(ii). …
d ( ± χ ) = 1 2 π e χ 2 / 2 erfc ( ± χ / 2 ) ,
For other uniform asymptotic approximations of the incomplete gamma functions in terms of the function erfc see Paris (2002b) and Dunster (1996a). … These expansions involve the inverse error function inverfc ( x ) 7.17), and are uniform with respect to q [ 0 , 1 ] . …
33: 7.12 Asymptotic Expansions
§7.12(i) Complementary Error Function
For these and other error bounds see Olver (1997b, pp. 109–112), with α = 1 2 and z replaced by z 2 ; compare (7.11.2). … (Note that some of these re-expansions themselves involve the complementary error function.)
§7.12(ii) Fresnel Integrals
§7.12(iii) Goodwin–Staton Integral
34: 7.19 Voigt Functions
7.19.1 𝖴 ( x , t ) = 1 4 π t e ( x y ) 2 / ( 4 t ) 1 + y 2 d y ,
7.19.3 𝖴 ( x , t ) + i 𝖵 ( x , t ) = π 4 t e z 2 erfc z , z = ( 1 i x ) / ( 2 t ) .
§7.19(iv) Other Integral Representations
7.19.10 𝖴 ( u a , 1 4 a 2 ) = a 0 e a t 1 4 t 2 cos ( u t ) d t ,
7.19.11 𝖵 ( u a , 1 4 a 2 ) = a 0 e a t 1 4 t 2 sin ( u t ) d t .
35: 7.22 Methods of Computation
The methods available for computing the main functions in this chapter are analogous to those described in §§6.18(i)6.18(iv) for the exponential integral and sine and cosine integrals, and similar comments apply. …
§7.22(ii) Goodwin–Staton Integral
§7.22(iii) Repeated Integrals of the Complementary Error Function
The recursion scheme given by (7.18.1) and (7.18.7) can be used for computing i n erfc ( x ) . … The computation of these functions can be based on algorithms for the complementary error function with complex argument; compare (7.19.3). …
36: 8.11 Asymptotic Approximations and Expansions
8.11.11 γ ( 1 a , x ) = x a 1 ( cos ( π a ) + sin ( π a ) π ( 2 π F ( y ) + 2 3 2 π a ( 1 y 2 ) ) e y 2 + O ( a 1 ) ) ,
For Dawson’s integral F ( y ) see §7.2(ii). … This reference also contains explicit formulas for the coefficients in terms of Stirling numbers. … With x = 1 , an asymptotic expansion of e n ( n x ) / e n x follows from (8.11.14) and (8.11.16). …
37: 22.11 Fourier and Hyperbolic Series
If q exp ( 2 | ζ | ) < 1 , then … Next, if q exp ( | ζ | ) < 1 , then … Next, with E = E ( k ) denoting the complete elliptic integral of the second kind (§19.2(ii)) and q exp ( 2 | ζ | ) < 1 , … where E = E ( k ) is defined by §19.2.9. …
38: 22.20 Methods of Computation
If either τ or q = e i π τ is given, then we use k = θ 2 2 ( 0 , q ) / θ 3 2 ( 0 , q ) , k = θ 4 2 ( 0 , q ) / θ 3 2 ( 0 , q ) , K = 1 2 π θ 3 2 ( 0 , q ) , and K = i τ K , obtaining the values of the theta functions as in §20.14. …
39: 2.11 Remainder Terms; Stokes Phenomenon
From §8.19(i) the generalized exponential integral is given by …However, on combining (2.11.6) with the connection formula (8.19.18), with m = 1 , we derive … Owing to the factor e ρ , that is, e | z | in (2.11.13), F n + p ( z ) is uniformly exponentially small compared with E p ( z ) . … Here erfc is the complementary error function (§7.2(i)), and … A simple example is provided by Euler’s transformation (§3.9(ii)) applied to the asymptotic expansion for the exponential integral6.12(i)): …
40: 13.6 Relations to Other Functions
13.6.1 M ( a , a , z ) = e z ,
When a b is an integer or a is a positive integer the Kummer functions can be expressed as incomplete gamma functions (or generalized exponential integrals). …
13.6.6 U ( a , a , z ) = z 1 a U ( 1 , 2 a , z ) = z 1 a e z E a ( z ) = e z Γ ( 1 a , z ) .