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11: 10.41 Asymptotic Expansions for Large Order
Moreover, because of the uniqueness property of asymptotic expansions2.1(iii)) this expansion must agree with (10.40.2), with z replaced by ν z , up to and including the term in z ( 1 ) . … Similar analysis can be developed for the uniform asymptotic expansions in terms of Airy functions given in §10.20. …This is done by re-expansion with the aid of (10.20.10), (10.20.11), and §10.41(ii), followed by comparison with (10.17.5) and (10.17.6), with z replaced by ν z . …
12: 10.17 Asymptotic Expansions for Large Argument
Then the remainder associated with the sum k = 0 1 ( 1 ) k a 2 k ( ν ) z 2 k does not exceed the first neglected term in absolute value and has the same sign provided that max ( 1 2 ν 1 4 , 1 ) . … If these expansions are terminated when k = 1 , then the remainder term is bounded in absolute value by the first neglected term, provided that max ( ν 1 2 , 1 ) . …
10.17.14 | R ± ( ν , z ) | 2 | a ( ν ) | 𝒱 z , ± i ( t ) exp ( | ν 2 1 4 | 𝒱 z , ± i ( t 1 ) ) ,
10.17.18 R m , ± ( ν , z ) = O ( e 2 | z | z m ) , | ph ( z e 1 2 π i ) | π .
For higher re-expansions of the remainder terms see Olde Daalhuis and Olver (1995a) and Olde Daalhuis (1995, 1996).
13: 20 Theta Functions
Chapter 20 Theta Functions
14: 27.15 Chinese Remainder Theorem
§27.15 Chinese Remainder Theorem
The Chinese remainder theorem states that a system of congruences x a 1 ( mod m 1 ) , , x a k ( mod m k ) , always has a solution if the moduli are relatively prime in pairs; the solution is unique (mod m ), where m is the product of the moduli. … Their product m has 20 digits, twice the number of digits in the data. By the Chinese remainder theorem each integer in the data can be uniquely represented by its residues (mod m 1 ), (mod m 2 ), (mod m 3 ), and (mod m 4 ), respectively. …These numbers, in turn, are combined by the Chinese remainder theorem to obtain the final result ( mod m ) , which is correct to 20 digits. …
15: 8 Incomplete Gamma and Related
Functions
16: 28 Mathieu Functions and Hill’s Equation
17: 8.26 Tables
  • Khamis (1965) tabulates P ( a , x ) for a = 0.05 ( .05 ) 10 ( .1 ) 20 ( .25 ) 70 , 0.0001 x 250 to 10D.

  • Abramowitz and Stegun (1964, pp. 245–248) tabulates E n ( x ) for n = 2 , 3 , 4 , 10 , 20 , x = 0 ( .01 ) 2 to 7D; also ( x + n ) e x E n ( x ) for n = 2 , 3 , 4 , 10 , 20 , x 1 = 0 ( .01 ) 0.1 ( .05 ) 0.5 to 6S.

  • Pagurova (1961) tabulates E n ( x ) for n = 0 ( 1 ) 20 , x = 0 ( .01 ) 2 ( .1 ) 10 to 4-9S; e x E n ( x ) for n = 2 ( 1 ) 10 , x = 10 ( .1 ) 20 to 7D; e x E p ( x ) for p = 0 ( .1 ) 1 , x = 0.01 ( .01 ) 7 ( .05 ) 12 ( .1 ) 20 to 7S or 7D.

  • Zhang and Jin (1996, Table 19.1) tabulates E n ( x ) for n = 1 , 2 , 3 , 5 , 10 , 15 , 20 , x = 0 ( .1 ) 1 , 1.5 , 2 , 3 , 5 , 10 , 20 , 30 , 50 , 100 to 7D or 8S.

  • 18: 23 Weierstrass Elliptic and Modular
    Functions
    19: 6.16 Mathematical Applications
    6.16.2 S n ( x ) = k = 0 n 1 sin ( ( 2 k + 1 ) x ) 2 k + 1 = 1 2 0 x sin ( 2 n t ) sin t d t = 1 2 Si ( 2 n x ) + R n ( x ) ,
    6.16.3 R n ( x ) = 1 2 0 x ( 1 sin t 1 t ) sin ( 2 n t ) d t .
    6.16.4 R n ( x ) = O ( n 1 ) , n ,
    See accompanying text
    Figure 6.16.2: The logarithmic integral li ( x ) , together with vertical bars indicating the value of π ( x ) for x = 10 , 20 , , 1000 . Magnify
    20: 36 Integrals with Coalescing Saddles