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21: 9.7 Asymptotic Expansions
Here δ denotes an arbitrary small positive constant and … Numerical values of χ ( n ) are given in Table 9.7.1 for n = 1 ( 1 ) 20 to 2D. …
9.7.6 Ai ( z ) z 1 / 4 e ζ 2 π k = 0 ( 1 ) k v k ζ k , | ph z | π δ ,
22: 32.8 Rational Solutions
Q 3 ( z ) = z 6 + 20 z 3 80 ,
In the general case assume γ δ 0 , so that as in §32.2(ii) we may set γ = 1 and δ = 1 . … In the general case assume δ 0 , so that as in §32.2(ii) we may set δ = 1 2 . … For the case δ = 0 see Airault (1979) and Lukaševič (1968). … where n , a = ε 1 2 α , b = ε 2 2 β , c = ε 3 2 γ , and d = ε 4 1 2 δ , with ε j = ± 1 , j = 1 , 2 , 3 , 4 , independently, and at least one of a , b , c or d is an integer. …
23: 18.27 q -Hahn Class
18.27.2 x X p n ( x ) p m ( x ) | x | v x = h n δ n , m ,
Here a , b are fixed positive real numbers, and I + and I are sequences of successive integers, finite or unbounded in one direction, or unbounded in both directions. …In case of unbounded sequences (18.27.2) can be rewritten as a q -integral, see §17.2(v), and more generally Gasper and Rahman (2004, (1.11.2)). …
18.27.4 y = 0 N Q n ( q y ) Q m ( q y ) [ N y ] q ( α q ; q ) y ( β q ; q ) N y ( α q ) y = h n δ n , m , n , m = 0 , 1 , , N ,
18.27.14 y = 0 p n ( q y ) p m ( q y ) ( b q ; q ) y ( a q ) y ( q ; q ) y = h n δ n , m , 0 < a < q 1 , b < q 1 ,
24: 30.15 Signal Analysis
30.15.7 τ τ ϕ k ( t ) ϕ n ( t ) d t = Λ n δ k , n ,
30.15.8 ϕ k ( t ) ϕ n ( t ) d t = δ k , n .
The sequence ϕ n , n = 0 , 1 , 2 , forms an orthonormal basis in the space of σ -bandlimited functions, and, after normalization, an orthonormal basis in L 2 ( τ , τ ) . …
25: 31.3 Basic Solutions
H ( a , q ; α , β , γ , δ ; z ) denotes the solution of (31.2.1) that corresponds to the exponent 0 at z = 0 and assumes the value 1 there. If the other exponent is not a positive integer, that is, if γ 0 , 1 , 2 , , then from §2.7(i) it follows that H ( a , q ; α , β , γ , δ ; z ) exists, is analytic in the disk | z | < 1 , and has the Maclaurin expansion … Solutions of (31.2.1) corresponding to the exponents 0 and 1 δ at z = 1 are respectively, …
31.3.7 ( 1 z ) 1 δ H ( 1 a , ( ( 1 a ) γ + ϵ ) ( 1 δ ) + α β q ; α + 1 δ , β + 1 δ , 2 δ , γ ; 1 z ) .
For example, H ( a , q ; α , β , γ , δ ; z ) is equal to …
26: 18.26 Wilson Class: Continued
18.26.4_1 R n ( y ( y + γ + δ + 1 ) ; γ , δ , N ) = Q y ( n ; γ , δ , N ) ,
18.26.4_2 R n ( y ( y + γ + δ + 1 ) ; α , β , γ , δ ) = R y ( n ( n + α + β + 1 ) ; γ , δ , α , β ) .
For comments on the use of the forward-difference operator Δ x , the backward-difference operator x , and the central-difference operator δ x , see §18.2(ii). …
18.26.16 Δ y ( R n ( y ( y + γ + δ + 1 ) ; α , β , γ , δ ) ) Δ y ( y ( y + γ + δ + 1 ) ) = n ( n + α + β + 1 ) ( α + 1 ) ( β + δ + 1 ) ( γ + 1 ) R n 1 ( y ( y + γ + δ + 2 ) ; α + 1 , β + 1 , γ + 1 , δ ) .
18.26.17 Δ y ( R n ( y ( y + γ + δ + 1 ) ; γ , δ , N ) ) Δ y ( y ( y + γ + δ + 1 ) ) = n ( γ + 1 ) N R n 1 ( y ( y + γ + δ + 2 ) ; γ + 1 , δ , N 1 ) .
27: 28.1 Special Notation
m , n integers.
δ arbitrary small positive number.
Abramowitz and Stegun (1964, Chapter 20)
28: 31.16 Mathematical Applications
31.16.5 P j = ( ϵ j + n ) j ( β + j 1 ) ( γ + δ + j 2 ) ( γ + δ + 2 j 3 ) ( γ + δ + 2 j 2 ) ,
31.16.6 Q j = a j ( j + γ + δ 1 ) q + ( j n ) ( j + β ) ( j + γ ) ( j + γ + δ 1 ) ( 2 j + γ + δ ) ( 2 j + γ + δ 1 ) + ( j + n + γ + δ 1 ) j ( j + δ 1 ) ( j β + γ + δ 1 ) ( 2 j + γ + δ 1 ) ( 2 j + γ + δ 2 ) ,
31.16.7 R j = ( n j ) ( j + n + γ + δ ) ( j + γ ) ( j + δ ) ( γ + δ + 2 j ) ( γ + δ + 2 j + 1 ) .
29: 18.2 General Orthogonal Polynomials
If the orthogonality discrete set X is { 0 , 1 , , N } or { 0 , 1 , 2 , } , then the role of the differentiation operator d / d x in the case of classical OP’s (§18.3) is played by Δ x , the forward-difference operator, or by x , the backward-difference operator; compare §18.1(i). … The Hankel determinant Δ n of order n is defined by Δ 0 = 1 and …Also define determinants Δ n by Δ 0 = 0 , Δ 1 = μ 1 and … The operator D x is a delta operator, i. … …
30: 19.11 Addition Theorems
Δ ( θ ) = 1 k 2 sin 2 θ .
δ = α 2 ( 1 α 2 ) ( α 2 k 2 ) .
δ = α 2 ( 1 α 2 ) ( α 2 k 2 ) .
If ϕ = θ in §19.11(i) and Δ ( θ ) is again defined by (19.11.3), then …
cos θ = ( cos ψ ) + Δ ( ψ ) 1 + Δ ( ψ ) ,