About the Project

.1966年世界杯决赛悬案_『wn4.com_』国际象棋世界杯第十轮_w6n2c9o_2022年11月28日19时19分39秒_swou6u2qo_cc

AdvancedHelp

(0.005 seconds)

11—20 of 782 matching pages

11: 27.2 Functions
where p 1 , p 2 , , p ν ( n ) are the distinct prime factors of n , each exponent a r is positive, and ν ( n ) is the number of distinct primes dividing n . … Note that σ 0 ( n ) = d ( n ) . …Note that J 1 ( n ) = ϕ ( n ) . In the following examples, a 1 , , a ν ( n ) are the exponents in the factorization of n in (27.2.1). … Table 27.2.1 lists the first 100 prime numbers p n . …
12: 3.11 Approximation Techniques
Beginning with u n + 1 = 0 , u n = c n , we apply … With b 0 = 1 , the last q equations give b 1 , , b q as the solution of a system of linear equations. … (3.11.29) is a system of n + 1 linear equations for the coefficients a 0 , a 1 , , a n . … With this choice of a k and f j = f ( x j ) , the corresponding sum (3.11.32) vanishes. … Two are endpoints: ( x 0 , y 0 ) and ( x 3 , y 3 ) ; the other points ( x 1 , y 1 ) and ( x 2 , y 2 ) are control points. …
13: 24.2 Definitions and Generating Functions
B 2 n + 1 = 0 ,
24.2.4 B n = B n ( 0 ) ,
Table 24.2.4: Euler numbers E n .
n E n
Table 24.2.5: Coefficients b n , k of the Bernoulli polynomials B n ( x ) = k = 0 n b n , k x k .
k
Table 24.2.6: Coefficients e n , k of the Euler polynomials E n ( x ) = k = 0 n e n , k x k .
k
14: 3.7 Ordinary Differential Equations
The path is partitioned at P + 1 points labeled successively z 0 , z 1 , , z P , with z 0 = a , z P = b . … Write τ j = z j + 1 z j , j = 0 , 1 , , P , expand w ( z ) and w ( z ) in Taylor series (§1.10(i)) centered at z = z j , and apply (3.7.2). … If, for example, β 0 = β 1 = 0 , then on moving the contributions of w ( z 0 ) and w ( z P ) to the right-hand side of (3.7.13) the resulting system of equations is not tridiagonal, but can readily be made tridiagonal by annihilating the elements of 𝐀 P that lie below the main diagonal and its two adjacent diagonals. … The values λ k are the eigenvalues and the corresponding solutions w k of the differential equation are the eigenfunctions. … where h = z n + 1 z n and …
15: 23.9 Laurent and Other Power Series
Let z 0 ( 0 ) be the nearest lattice point to the origin, and define …Explicit coefficients c n in terms of c 2 and c 3 are given up to c 19 in Abramowitz and Stegun (1964, p. 636). For j = 1 , 2 , 3 , and with e j as in §23.3(i), … where a 0 , 0 = 1 , a m , n = 0 if either m or n < 0 , and …For a m , n with m = 0 , 1 , , 12 and n = 0 , 1 , , 8 , see Abramowitz and Stegun (1964, p. 637).
16: 3.2 Linear Algebra
where u j = c j , j = 1 , 2 , , n 1 , d 1 = b 1 , and …Forward elimination for solving 𝐀 𝐱 = 𝐟 then becomes y 1 = f 1 , …and back substitution is x n = y n / d n , followed by … Define the Lanczos vectors 𝐯 j and coefficients α j and β j by 𝐯 0 = 𝟎 , a normalized vector 𝐯 1 (perhaps chosen randomly), α 1 = 𝐯 1 T 𝐀 𝐯 1 , β 1 = 0 , and for j = 1 , 2 , , n 1 by the recursive scheme … Start with 𝐯 0 = 𝟎 , vector 𝐯 1 such that 𝐯 1 T 𝐒 𝐯 1 = 1 , α 1 = 𝐯 1 T 𝐀 𝐯 1 , β 1 = 0 . …
17: 32.7 Bäcklund Transformations
Let w j ( z j ) = w ( z j ; α j , β j , γ j , δ j ) , j = 0 , 1 , 2 , be solutions of P V  with … satisfies P V  with … Let w j ( z j ) = w j ( z j ; α j , β j , γ j , δ j ) , j = 0 , 1 , 2 , 3 , be solutions of P VI  with … P VI  also has quadratic and quartic transformations. …Also, …
18: 17.6 ϕ 1 2 Function
§17.6 ϕ 1 2 Function
§17.6(ii) ϕ 1 2 Transformations
Three-Term ϕ 1 2 Transformations
(17.6.27) reduces to the hypergeometric equation (15.10.1) with the substitutions a q a , b q b , c q c , followed by lim q 1 . … For continued-fraction representations of the ϕ 1 2 function, see Cuyt et al. (2008, pp. 395–399).
19: 3.9 Acceleration of Convergence
A transformation of a convergent sequence { s n } with limit σ into a sequence { t n } is called limit-preserving if { t n } converges to the same limit σ . … This transformation is accelerating if { s n } is a linearly convergent sequence, i. … Then the transformation of the sequence { s n } into a sequence { t n , 2 k } is given by … Then t n , 2 k = ε 2 k ( n ) . … We give a special form of Levin’s transformation in which the sequence s = { s n } of partial sums s n = j = 0 n a j is transformed into: …
20: 3.4 Differentiation
The B k n are the differentiated Lagrangian interpolation coefficients: … where ξ 0 and ξ 1 I . For the values of n 0 and n 1 used in the formulas below … For partial derivatives we use the notation u t , s = u ( x 0 + t h , y 0 + s h ) . …