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11: 4.43 Cubic Equations
A = ( 4 3 p ) 1 / 2 ,
B = ( 4 3 p ) 1 / 2 .
  • (a)

    A sin a , A sin ( a + 2 3 π ) , and A sin ( a + 4 3 π ) , with sin ( 3 a ) = 4 q / A 3 , when 4 p 3 + 27 q 2 0 .

  • (b)

    A cosh a , A cosh ( a + 2 3 π i ) , and A cosh ( a + 4 3 π i ) , with cosh ( 3 a ) = 4 q / A 3 , when p < 0 , q < 0 , and 4 p 3 + 27 q 2 > 0 .

  • (c)

    B sinh a , B sinh ( a + 2 3 π i ) , and B sinh ( a + 4 3 π i ) , with sinh ( 3 a ) = 4 q / B 3 , when p > 0 .

  • 12: 12.7 Relations to Other Functions
    12.7.8 U ( 2 , z ) = z 5 / 2 4 2 π ( 2 K 1 4 ( 1 4 z 2 ) + 3 K 3 4 ( 1 4 z 2 ) K 5 4 ( 1 4 z 2 ) ) ,
    12.7.9 U ( 1 , z ) = z 3 / 2 2 2 π ( K 1 4 ( 1 4 z 2 ) + K 3 4 ( 1 4 z 2 ) ) ,
    12.7.11 U ( 1 , z ) = z 3 / 2 2 π ( K 3 4 ( 1 4 z 2 ) K 1 4 ( 1 4 z 2 ) ) .
    12.7.12 u 1 ( a , z ) = e 1 4 z 2 M ( 1 2 a + 1 4 , 1 2 , 1 2 z 2 ) = e 1 4 z 2 M ( 1 2 a + 1 4 , 1 2 , 1 2 z 2 ) ,
    12.7.13 u 2 ( a , z ) = z e 1 4 z 2 M ( 1 2 a + 3 4 , 3 2 , 1 2 z 2 ) = z e 1 4 z 2 M ( 1 2 a + 3 4 , 3 2 , 1 2 z 2 ) .
    13: 4.17 Special Values and Limits
    Table 4.17.1: Trigonometric functions: values at multiples of 1 12 π .
    θ sin θ cos θ tan θ csc θ sec θ cot θ
    π / 12 1 4 2 ( 3 1 ) 1 4 2 ( 3 + 1 ) 2 3 2 ( 3 + 1 ) 2 ( 3 1 ) 2 + 3
    π / 4 1 2 2 1 2 2 1 2 2 1
    5 π / 12 1 4 2 ( 3 + 1 ) 1 4 2 ( 3 1 ) 2 + 3 2 ( 3 1 ) 2 ( 3 + 1 ) 2 3
    7 π / 12 1 4 2 ( 3 + 1 ) 1 4 2 ( 3 1 ) ( 2 + 3 ) 2 ( 3 1 ) 2 ( 3 + 1 ) ( 2 3 )
    11 π / 12 1 4 2 ( 3 1 ) 1 4 2 ( 3 + 1 ) ( 2 3 ) 2 ( 3 + 1 ) 2 ( 3 1 ) ( 2 + 3 )
    14: 14.4 Graphics
    See accompanying text
    Figure 14.4.1: 𝖯 ν 0 ( x ) , ν = 0 , 1 2 , 1 , 2 , 4 . Magnify
    See accompanying text
    Figure 14.4.2: 𝖰 ν 0 ( x ) , ν = 0 , 1 2 , 1 , 2 , 4 . Magnify
    See accompanying text
    Figure 14.4.3: 𝖯 ν 1 / 2 ( x ) , ν = 0 , 1 2 , 1 , 2 , 4 . Magnify
    See accompanying text
    Figure 14.4.24: 𝑸 0 μ ( x ) , μ = 0 , 2 , 4 , 8 . Magnify
    See accompanying text
    Figure 14.4.28: 𝑸 1 μ ( x ) , μ = 0 , 2 , 4 , 8 . Magnify
    15: 19.38 Approximations
    Minimax polynomial approximations (§3.11(i)) for K ( k ) and E ( k ) in terms of m = k 2 with 0 m < 1 can be found in Abramowitz and Stegun (1964, §17.3) with maximum absolute errors ranging from 4×10⁻⁵ to 2×10⁻⁸. Approximations of the same type for K ( k ) and E ( k ) for 0 < k 1 are given in Cody (1965a) with maximum absolute errors ranging from 4×10⁻⁵ to 4×10⁻¹⁸. …
    16: 29.7 Asymptotic Expansions
    29.7.4 τ 1 = p 2 6 ( ( 1 + k 2 ) 2 ( p 2 + 3 ) 4 k 2 ( p 2 + 5 ) ) .
    29.7.6 τ 2 = 1 2 10 ( 1 + k 2 ) ( 1 k 2 ) 2 ( 5 p 4 + 34 p 2 + 9 ) ,
    29.7.7 τ 3 = p 2 14 ( ( 1 + k 2 ) 4 ( 33 p 4 + 410 p 2 + 405 ) 24 k 2 ( 1 + k 2 ) 2 ( 7 p 4 + 90 p 2 + 95 ) + 16 k 4 ( 9 p 4 + 130 p 2 + 173 ) ) ,
    29.7.8 τ 4 = 1 2 16 ( ( 1 + k 2 ) 5 ( 63 p 6 + 1260 p 4 + 2943 p 2 + 486 ) 8 k 2 ( 1 + k 2 ) 3 ( 49 p 6 + 1010 p 4 + 2493 p 2 + 432 ) + 16 k 4 ( 1 + k 2 ) ( 35 p 6 + 760 p 4 + 2043 p 2 + 378 ) ) .
    17: 3.4 Differentiation
    B 1 4 = 1 6 ( 4 8 t 3 t 2 + 4 t 3 ) ,
    B 1 4 = 1 6 ( 4 + 8 t 3 t 2 4 t 3 ) ,
    B 0 5 = 1 12 ( 4 + 30 t 15 t 2 12 t 3 + 5 t 4 ) ,
    B 3 5 = 1 120 ( 4 15 t 2 + 5 t 4 ) .
    For additional formulas involving values of 2 u and 4 u on square, triangular, and cubic grids, see Collatz (1960, Table VI, pp. 542–546). …
    18: 26.2 Basic Definitions
    If, for example, a permutation of the integers 1 through 6 is denoted by 256413 , then the cycles are ( 1 , 2 , 5 ) , ( 3 , 6 ) , and ( 4 ) . …The function σ also interchanges 3 and 6, and sends 4 to itself. … As an example, { 1 , 3 , 4 } , { 2 , 6 } , { 5 } is a partition of { 1 , 2 , 3 , 4 , 5 , 6 } . … As an example, { 1 , 1 , 1 , 2 , 4 , 4 } is a partition of 13. … The example { 1 , 1 , 1 , 2 , 4 , 4 } has six parts, three of which equal 1. …
    19: 27.15 Chinese Remainder Theorem
    Choose four relatively prime moduli m 1 , m 2 , m 3 , and m 4 of five digits each, for example 2 16 3 , 2 16 1 , 2 16 + 1 , and 2 16 + 3 . …By the Chinese remainder theorem each integer in the data can be uniquely represented by its residues (mod m 1 ), (mod m 2 ), (mod m 3 ), and (mod m 4 ), respectively. Because each residue has no more than five digits, the arithmetic can be performed efficiently on these residues with respect to each of the moduli, yielding answers a 1 ( mod m 1 ) , a 2 ( mod m 2 ) , a 3 ( mod m 3 ) , and a 4 ( mod m 4 ) , where each a j has no more than five digits. …
    20: 28.15 Expansions for Small q
    28.15.1 λ ν ( q ) = ν 2 + 1 2 ( ν 2 1 ) q 2 + 5 ν 2 + 7 32 ( ν 2 1 ) 3 ( ν 2 4 ) q 4 + 9 ν 4 + 58 ν 2 + 29 64 ( ν 2 1 ) 5 ( ν 2 4 ) ( ν 2 9 ) q 6 + .
    28.15.2 a ν 2 q 2 a ( ν + 2 ) 2 q 2 a ( ν + 4 ) 2 = q 2 a ( ν 2 ) 2 q 2 a ( ν 4 ) 2 .
    28.15.3 me ν ( z , q ) = e i ν z q 4 ( 1 ν + 1 e i ( ν + 2 ) z 1 ν 1 e i ( ν 2 ) z ) + q 2 32 ( 1 ( ν + 1 ) ( ν + 2 ) e i ( ν + 4 ) z + 1 ( ν 1 ) ( ν 2 ) e i ( ν 4 ) z 2 ( ν 2 + 1 ) ( ν 2 1 ) 2 e i ν z ) + ;