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right-hand rule for cross products

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11: 22.12 Expansions in Other Trigonometric Series and Doubly-Infinite Partial Fractions: Eisenstein Series
12: 3.8 Nonlinear Equations
§3.8(ii) Newton’s Rule
Newton’s rule is given by … Another iterative method is Halley’s rule: … For moderate or large values of n it is not uncommon for the magnitude of the right-hand side of (3.8.14) to be very large compared with unity, signifying that the computation of zeros of polynomials is often an ill-posed problem. …
13: 6.7 Integral Representations
The path of integration does not cross the negative real axis or pass through the origin. …The first integrals on the right-hand sides apply when | ph z | < π ; the second ones when z 0 and (in the case of (6.7.14)) z 0 . …
14: 8.2 Definitions and Basic Properties
However, when the integration paths do not cross the negative real axis, and in the case of (8.2.2) exclude the origin, γ ( a , z ) and Γ ( a , z ) take their principal values; compare §4.2(i). … (8.2.9) also holds when a is zero or a negative integer, provided that the right-hand side is replaced by its limiting value. …
15: 10.67 Asymptotic Expansions for Large Argument
The contributions of the terms in ker ν x , kei ν x , ker ν x , and kei ν x on the right-hand sides of (10.67.3), (10.67.4), (10.67.7), and (10.67.8) are exponentially small compared with the other terms, and hence can be neglected in the sense of Poincaré asymptotic expansions (§2.1(iii)). …
§10.67(ii) Cross-Products and Sums of Squares in the Case ν = 0
16: 3.7 Ordinary Differential Equations
If, for example, β 0 = β 1 = 0 , then on moving the contributions of w ( z 0 ) and w ( z P ) to the right-hand side of (3.7.13) the resulting system of equations is not tridiagonal, but can readily be made tridiagonal by annihilating the elements of A that lie below the main diagonal and its two adjacent diagonals. … The method consists of a set of rules each of which is equivalent to a truncated Taylor-series expansion, but the rules avoid the need for analytic differentiations of the differential equation. … For w = f ( z , w ) the standard fourth-order rule reads … For w ′′ = f ( z , w , w ) the standard fourth-order rule reads …
17: 18.15 Asymptotic Approximations
Also, when 1 6 π < θ < 5 6 π , the right-hand side of (18.15.12) with M = converges; paradoxically, however, the sum is 2 P n ( cos θ ) and not P n ( cos θ ) as stated erroneously in Szegő (1975, §8.4(3)). …
18.15.22 L n ( α ) ( ν x ) = ( - 1 ) n e 1 2 ν x 2 α - 1 2 x 1 2 α + 1 4 ( ζ x - 1 ) 1 4 ( Ai ( ν 2 3 ζ ) ν 1 3 m = 0 M - 1 E m ( ζ ) ν 2 m + Ai ( ν 2 3 ζ ) ν 5 3 m = 0 M - 1 F m ( ζ ) ν 2 m + envAi ( ν 2 3 ζ ) O ( 1 ν 2 M - 2 3 ) ) ,
18: 21.6 Products
§21.6 Products
21.6.3 j = 1 h θ ( k = 1 h T j k z k | Ω ) = 1 𝒟 g A 𝒦 B 𝒦 e 2 π i tr [ 1 2 A T Ω A + A T [ Z + B ] ] j = 1 h θ ( z j + Ω a j + b j | Ω ) ,
21.6.4 j = 1 h θ [ k = 1 h T j k c k k = 1 h T j k d k ] ( k = 1 h T j k z k | Ω ) = 1 𝒟 g A 𝒦 B 𝒦 e - 2 π i j = 1 h b j c j j = 1 h θ [ a j + c j b j + d j ] ( z j | Ω ) ,
Many identities involving products of theta functions can be established using these formulas. …
21.6.5 T = 1 2 [ 1 1 1 1 1 1 - 1 - 1 1 - 1 1 - 1 1 - 1 - 1 1 ] .
19: 16.8 Differential Equations
16.8.9 ( k = 1 q + 1 Γ ( a k ) / k = 1 q Γ ( b k ) ) F q q + 1 ( a 1 , , a q + 1 b 1 , , b q ; z ) = j = 1 q + 1 ( z 0 - z ) - a j n = 0 Γ ( a j + n ) n ! ( k = 1 k j q + 1 Γ ( a k - a j - n ) / k = 1 q Γ ( b k - a j - n ) ) F q q + 1 ( a 1 - a j - n , , a q + 1 - a j - n b 1 - a j - n , , b q - a j - n ; z 0 ) ( z - z 0 ) - n .
(Note that the generalized hypergeometric functions on the right-hand side are polynomials in z 0 .) …
20: 26.10 Integer Partitions: Other Restrictions
26.10.2 n = 0 p ( 𝒟 , n ) q n = j = 1 ( 1 + q j ) = j = 1 1 1 - q 2 j - 1 = 1 + m = 1 q m ( m + 1 ) / 2 ( 1 - q ) ( 1 - q 2 ) ( 1 - q m ) = 1 + m = 1 q m ( 1 + q ) ( 1 + q 2 ) ( 1 + q m - 1 ) ,
where the last right-hand side is the sum over m 0 of the generating functions for partitions into distinct parts with largest part equal to m .
26.10.3 ( 1 - x ) m , n = 0 p m ( k , 𝒟 , n ) x m q n = m = 0 k [ k m ] q q m ( m + 1 ) / 2 x m = j = 1 k ( 1 + x q j ) , | x | < 1 ,
26.10.5 n = 0 p ( S , n ) q n = j S 1 1 - q j .