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1: 12.11 Zeros
When a = 1 2 these zeros are the same as the zeros of the complementary error function erfc ( z / 2 ) ; compare (12.7.5). …
12.11.5 p 0 ( ζ ) = t ( ζ ) ,
12.11.6 p 1 ( ζ ) = t 3 6 t 24 ( t 2 1 ) 2 + 5 48 ( ( t 2 1 ) ζ 3 ) 1 2 .
12.11.8 q 0 ( ζ ) = t ( ζ ) .
12.11.9 u a , 1 2 1 2 μ ( 1 1.85575 708 μ 4 / 3 0.34438 34 μ 8 / 3 0.16871 5 μ 4 0.11414 μ 16 / 3 0.0808 μ 20 / 3 ) ,
2: 19.36 Methods of Computation
If (19.36.1) is used instead of its first five terms, then the factor ( 3 r ) 1 / 6 in Carlson (1995, (2.2)) is changed to ( 3 r ) 1 / 8 . For both R D and R J the factor ( r / 4 ) 1 / 6 in Carlson (1995, (2.18)) is changed to ( r / 5 ) 1 / 8 when the following polynomial of degree 7 (the same for both) is used instead of its first seven terms: … (In Legendre’s notation the modulus k approaches 0 or 1.) … The cases k c 2 / 2 p < and < p < k c 2 / 2 require different treatment for numerical purposes, and again precautions are needed to avoid cancellations. … For computation of Legendre’s integral of the third kind, see Abramowitz and Stegun (1964, §§17.7 and 17.8, Examples 15, 17, 19, and 20). …
3: 27.2 Functions
Euclid’s Elements (Euclid (1908, Book IX, Proposition 20)) gives an elegant proof that there are infinitely many primes. … Gauss and Legendre conjectured that π ( x ) is asymptotic to x / ln x as x :
27.2.3 π ( x ) x ln x .
27.2.4 p n n ln n .
27.2.14 Λ ( n ) = ln p , n = p a ,
4: 9.7 Asymptotic Expansions
9.7.1 ζ = 2 3 z 3 / 2 .
Numerical values of χ ( n ) are given in Table 9.7.1 for n = 1 ( 1 ) 20 to 2D. …
9.7.6 Ai ( z ) z 1 / 4 e ζ 2 π k = 0 ( 1 ) k v k ζ k , | ph z | π δ ,
where ξ = 2 3 x 3 / 2 . …
5: Bibliography D
  • C. de la Vallée Poussin (1896a) Recherches analytiques sur la théorie des nombres premiers. Première partie. La fonction ζ ( s ) de Riemann et les nombres premiers en général, suivi d’un Appendice sur des réflexions applicables à une formule donnée par Riemann. Ann. Soc. Sci. Bruxelles 20, pp. 183–256 (French).
  • C. de la Vallée Poussin (1896b) Recherches analytiques sur la théorie des nombres premiers. Deuxième partie. Les fonctions de Dirichlet et les nombres premiers de la forme linéaire M x + N . Ann. Soc. Sci. Bruxelles 20, pp. 281–397 (French).
  • B. Döring (1966) Complex zeros of cylinder functions. Math. Comp. 20 (94), pp. 215–222.
  • T. M. Dunster (1989) Uniform asymptotic expansions for Whittaker’s confluent hypergeometric functions. SIAM J. Math. Anal. 20 (3), pp. 744–760.
  • T. M. Dunster (1990a) Bessel functions of purely imaginary order, with an application to second-order linear differential equations having a large parameter. SIAM J. Math. Anal. 21 (4), pp. 995–1018.
  • 6: Errata
    Changes
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    7: 20.11 Generalizations and Analogs
    20.11.2 1 n G ( m , n ) = 1 n k = 0 n 1 e π i k 2 m / n = e π i / 4 m j = 0 m 1 e π i j 2 n / m = e π i / 4 m G ( n , m ) .
    20.11.3 f ( a , b ) = n = a n ( n + 1 ) / 2 b n ( n 1 ) / 2 ,
    §20.11(iii) Ramanujan’s Change of Base
    As in §20.11(ii), the modulus k of elliptic integrals (§19.2(ii)), Jacobian elliptic functions (§22.2), and Weierstrass elliptic functions (§23.6(ii)) can be expanded in q -series via (20.9.1). … These results are called Ramanujan’s changes of base. …
    8: 5.11 Asymptotic Expansions
    5.11.1 Ln Γ ( z ) ( z 1 2 ) ln z z + 1 2 ln ( 2 π ) + k = 1 B 2 k 2 k ( 2 k 1 ) z 2 k 1
    5.11.3 Γ ( z ) = e z z z ( 2 π z ) 1 / 2 Γ ( z ) e z z z ( 2 π z ) 1 / 2 k = 0 g k z k ,
    Wrench (1968) gives exact values of g k up to g 20 . …
    5.11.8 Ln Γ ( z + h ) ( z + h 1 2 ) ln z z + 1 2 ln ( 2 π ) + k = 2 ( 1 ) k B k ( h ) k ( k 1 ) z k 1 ,
    5.11.9 | Γ ( x + i y ) | 2 π | y | x ( 1 / 2 ) e π | y | / 2 ,
    9: 3.8 Nonlinear Equations
  • (a)

    f ( x 0 ) f ′′ ( x 0 ) > 0 and f ( x ) , f ′′ ( x ) do not change sign between x 0 and ξ (monotonic convergence).

  • (b)

    f ( x 0 ) f ′′ ( x 0 ) < 0 , f ( x ) , f ′′ ( x ) do not change sign in the interval ( x 0 , x 1 ) , and ξ [ x 0 , x 1 ] (monotonic convergence after the first iteration).

  • Then the sensitivity of a simple zero z to changes in α is given by … Consider x = 20 and j = 19 . We have p ( 20 ) = 19 ! and a 19 = 1 + 2 + + 20 = 210 . …
    10: 20.10 Integrals
    20.10.1 0 x s 1 θ 2 ( 0 | i x 2 ) d x = 2 s ( 1 2 s ) π s / 2 Γ ( 1 2 s ) ζ ( s ) , s > 1 ,
    20.10.2 0 x s 1 ( θ 3 ( 0 | i x 2 ) 1 ) d x = π s / 2 Γ ( 1 2 s ) ζ ( s ) , s > 1 ,
    20.10.3 0 x s 1 ( 1 θ 4 ( 0 | i x 2 ) ) d x = ( 1 2 1 s ) π s / 2 Γ ( 1 2 s ) ζ ( s ) , s > 0 .