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11: 1.11 Zeros of Polynomials
Set z = w 1 3 a to reduce f ( z ) = z 3 + a z 2 + b z + c to g ( w ) = w 3 + p w + q , with p = ( 3 b a 2 ) / 3 , q = ( 2 a 3 9 a b + 27 c ) / 27 . … f ( z ) = z 3 6 z 2 + 6 z 2 , g ( w ) = w 3 6 w 6 , A = 3 4 3 , B = 3 2 3 . … Resolvent cubic is z 3 + 12 z 2 + 20 z + 9 = 0 with roots θ 1 = 1 , θ 2 = 1 2 ( 11 + 85 ) , θ 3 = 1 2 ( 11 85 ) , and θ 1 = 1 , θ 2 = 1 2 ( 17 + 5 ) , θ 3 = 1 2 ( 17 5 ) . … Let … Then f ( z ) , with a n 0 , is stable iff a 0 0 ; D 2 k > 0 , k = 1 , , 1 2 n ; sign D 2 k + 1 = sign a 0 , k = 0 , 1 , , 1 2 n 1 2 .
12: 3.4 Differentiation
where A k n is as in (3.3.10). … If f can be extended analytically into the complex plane, then from Cauchy’s integral formula (§1.9(iii)) …where C is a simple closed contour described in the positive rotational sense such that C and its interior lie in the domain of analyticity of f , and x 0 is interior to C . Taking C to be a circle of radius r centered at x 0 , we obtain …The integral on the right-hand side can be approximated by the composite trapezoidal rule (3.5.2). …
13: 9.4 Maclaurin Series
9.4.1 Ai ( z ) = Ai ( 0 ) ( 1 + 1 3 ! z 3 + 1 4 6 ! z 6 + 1 4 7 9 ! z 9 + ) + Ai ( 0 ) ( z + 2 4 ! z 4 + 2 5 7 ! z 7 + 2 5 8 10 ! z 10 + ) ,
9.4.2 Ai ( z ) = Ai ( 0 ) ( 1 + 2 3 ! z 3 + 2 5 6 ! z 6 + 2 5 8 9 ! z 9 + ) + Ai ( 0 ) ( 1 2 ! z 2 + 1 4 5 ! z 5 + 1 4 7 8 ! z 8 + ) ,
9.4.3 Bi ( z ) = Bi ( 0 ) ( 1 + 1 3 ! z 3 + 1 4 6 ! z 6 + 1 4 7 9 ! z 9 + ) + Bi ( 0 ) ( z + 2 4 ! z 4 + 2 5 7 ! z 7 + 2 5 8 10 ! z 10 + ) ,
9.4.4 Bi ( z ) = Bi ( 0 ) ( 1 + 2 3 ! z 3 + 2 5 6 ! z 6 + 2 5 8 9 ! z 9 + ) + Bi ( 0 ) ( 1 2 ! z 2 + 1 4 5 ! z 5 + 1 4 7 8 ! z 8 + ) .
14: 3.3 Interpolation
where C is a simple closed contour in D described in the positive rotational sense and enclosing the points z , z 1 , z 2 , , z n . … and A k n are the Lagrangian interpolation coefficients defined by … where ω n + 1 ( ζ ) is given by (3.3.3), and C is a simple closed contour in D described in the positive rotational sense and enclosing z 0 , z 1 , , z n . … By using this approximation to x as a new point, x 3 = x , and evaluating [ f 0 , f 1 , f 2 , f 3 ] x = 1.12388 6190 , we find that x = 2.33810 7409 , with 9 correct digits. … Then by using x 3 in Newton’s interpolation formula, evaluating [ x 0 , x 1 , x 2 , x 3 ] f = 0.26608 28233 and recomputing f ( x ) , another application of Newton’s rule with starting value x 3 gives the approximation x = 2.33810 7373 , with 8 correct digits. …
15: 26.10 Integer Partitions: Other Restrictions
The set { n 1 | n ± j ( mod k ) } is denoted by A j , k . … Note that p ( 𝒟 3 , n ) p ( 𝒟 3 , n ) , with strict inequality for n 9 . It is known that for k > 3 , p ( 𝒟 k , n ) p ( A 1 , k + 3 , n ) , with strict inequality for n sufficiently large, provided that k = 2 m 1 , m = 3 , 4 , 5 , or k 32 ; see Yee (2004). … where I 1 ( x ) is the modified Bessel function (§10.25(ii)), and …The quantity A k ( n ) is real-valued. …
16: 14.33 Tables
  • Abramowitz and Stegun (1964, Chapter 8) tabulates 𝖯 n ( x ) for n = 0 ( 1 ) 3 , 9 , 10 , x = 0 ( .01 ) 1 , 5–8D; 𝖯 n ( x ) for n = 1 ( 1 ) 4 , 9 , 10 , x = 0 ( .01 ) 1 , 5–7D; 𝖰 n ( x ) and 𝖰 n ( x ) for n = 0 ( 1 ) 3 , 9 , 10 , x = 0 ( .01 ) 1 , 6–8D; P n ( x ) and P n ( x ) for n = 0 ( 1 ) 5 , 9 , 10 , x = 1 ( .2 ) 10 , 6S; Q n ( x ) and Q n ( x ) for n = 0 ( 1 ) 3 , 9 , 10 , x = 1 ( .2 ) 10 , 6S. (Here primes denote derivatives with respect to x .)

  • Zhang and Jin (1996, Chapter 4) tabulates 𝖯 n ( x ) for n = 2 ( 1 ) 5 , 10 , x = 0 ( .1 ) 1 , 7D; 𝖯 n ( cos θ ) for n = 1 ( 1 ) 4 , 10 , θ = 0 ( 5 ) 90 , 8D; 𝖰 n ( x ) for n = 0 ( 1 ) 2 , 10 , x = 0 ( .1 ) 0.9 , 8S; 𝖰 n ( cos θ ) for n = 0 ( 1 ) 3 , 10 , θ = 0 ( 5 ) 90 , 8D; 𝖯 n m ( x ) for m = 1 ( 1 ) 4 , n m = 0 ( 1 ) 2 , n = 10 , x = 0 , 0.5 , 8S; 𝖰 n m ( x ) for m = 1 ( 1 ) 4 , n = 0 ( 1 ) 2 , 10 , 8S; 𝖯 ν m ( cos θ ) for m = 0 ( 1 ) 3 , ν = 0 ( .25 ) 5 , θ = 0 ( 15 ) 90 , 5D; P n ( x ) for n = 2 ( 1 ) 5 , 10 , x = 1 ( 1 ) 10 , 7S; Q n ( x ) for n = 0 ( 1 ) 2 , 10 , x = 2 ( 1 ) 10 , 8S. Corresponding values of the derivative of each function are also included, as are 6D values of the first 5 ν -zeros of 𝖯 ν m ( cos θ ) and of its derivative for m = 0 ( 1 ) 4 , θ = 10 , 30 , 150 .

  • Belousov (1962) tabulates 𝖯 n m ( cos θ ) (normalized) for m = 0 ( 1 ) 36 , n m = 0 ( 1 ) 56 , θ = 0 ( 2.5 ) 90 , 6D.

  • 17: 34 3j, 6j, 9j Symbols
    Chapter 34 3 j , 6 j , 9 j Symbols
    18: 8 Incomplete Gamma and Related
    Functions
    Chapter 8 Incomplete Gamma and Related Functions
    19: 26.5 Lattice Paths: Catalan Numbers
    C ( n ) is the Catalan number. …(Sixty-six equivalent definitions of C ( n ) are given in Stanley (1999, pp. 219–229).) …
    26.5.3 C ( n + 1 ) = k = 0 n C ( k ) C ( n k ) ,
    26.5.4 C ( n + 1 ) = 2 ( 2 n + 1 ) n + 2 C ( n ) ,
    26.5.7 lim n C ( n + 1 ) C ( n ) = 4 .
    20: 12.14 The Function W ( a , x )
    For the modulus functions F ~ ( a , x ) and G ~ ( a , x ) see §12.14(x). … Other expansions, involving cos ( 1 4 x 2 ) and sin ( 1 4 x 2 ) , can be obtained from (12.4.3) to (12.4.6) by replacing a by i a and z by x e π i / 4 ; see Miller (1955, p. 80), and also (12.14.15) and (12.14.16). … Here 𝒜 s ( t ) is as in §12.10(ii), σ is defined by … uniformly for t [ 1 + δ , 1 δ ] , with η given by (12.10.23) and 𝒜 ~ s ( t ) given by (12.10.24). … uniformly for t [ 1 + δ , ) , with ζ , ϕ ( ζ ) , A s ( ζ ) , and B s ( ζ ) as in §12.10(vii). …