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11: 1.5 Calculus of Two or More Variables
A function is continuous on a point set D if it is continuous at all points of D . … If f ( x , y ) is continuous, and D is the set … Similarly, if D is the set … If D can be represented in both forms (1.5.30) and (1.5.33), and f ( x , y ) is continuous on D , then … Infinite double integrals occur when f ( x , y ) becomes infinite at points in D or when D is unbounded. …
12: 27.21 Tables
Glaisher (1940) contains four tables: Table I tabulates, for all n 10 4 : (a) the canonical factorization of n into powers of primes; (b) the Euler totient ϕ ( n ) ; (c) the divisor function d ( n ) ; (d) the sum σ ( n ) of these divisors. …Table III lists all solutions n 10 4 of the equation d ( n ) = m , and Table IV lists all solutions n of the equation σ ( n ) = m for all m 10 4 . …6 lists ϕ ( n ) , d ( n ) , and σ ( n ) for n 1000 ; Table 24. …
13: 12.1 Special Notation
An older notation, due to Whittaker (1902), for U ( a , z ) is D ν ( z ) . The notations are related by U ( a , z ) = D a 1 2 ( z ) . Whittaker’s notation D ν ( z ) is useful when ν is a nonnegative integer (Hermite polynomial case).
14: 21.6 Products
21.6.2 𝒟 = | 𝐓 T h / ( 𝐓 T h h ) | ,
that is, 𝒟 is the number of elements in the set containing all h -dimensional vectors obtained by multiplying 𝐓 T on the right by a vector with integer elements. …
21.6.3 j = 1 h θ ( k = 1 h T j k 𝐳 k | 𝛀 ) = 1 𝒟 g 𝐀 𝒦 𝐁 𝒦 e 2 π i tr [ 1 2 𝐀 T 𝛀 𝐀 + 𝐀 T [ 𝐙 + 𝐁 ] ] j = 1 h θ ( 𝐳 j + 𝛀 𝐚 j + 𝐛 j | 𝛀 ) ,
21.6.4 j = 1 h θ [ k = 1 h T j k 𝐜 k k = 1 h T j k 𝐝 k ] ( k = 1 h T j k 𝐳 k | 𝛀 ) = 1 𝒟 g 𝐀 𝒦 𝐁 𝒦 e 2 π i j = 1 h 𝐛 j 𝐜 j j = 1 h θ [ 𝐚 j + 𝐜 j 𝐛 j + 𝐝 j ] ( 𝐳 j | 𝛀 ) ,
21.6.6 θ ( 𝐱 + 𝐲 + 𝐮 + 𝐯 2 | 𝛀 ) θ ( 𝐱 + 𝐲 𝐮 𝐯 2 | 𝛀 ) θ ( 𝐱 𝐲 + 𝐮 𝐯 2 | 𝛀 ) θ ( 𝐱 𝐲 𝐮 + 𝐯 2 | 𝛀 ) = 1 2 g 𝜶 1 2 g / g 𝜷 1 2 g / g e 2 π i ( 2 𝜶 𝛀 𝜶 + 𝜶 [ 𝐱 + 𝐲 + 𝐮 + 𝐯 ] ) θ ( 𝐱 + 𝛀 𝜶 + 𝜷 | 𝛀 ) θ ( 𝐲 + 𝛀 𝜶 + 𝜷 | 𝛀 ) θ ( 𝐮 + 𝛀 𝜶 + 𝜷 | 𝛀 ) θ ( 𝐯 + 𝛀 𝜶 + 𝜷 | 𝛀 ) ,
15: 24.10 Arithmetic Properties
24.10.1 B 2 n + ( p 1 ) | 2 n 1 p = integer ,
Let B 2 n = N 2 n / D 2 n , with N 2 n and D 2 n relatively prime and D 2 n > 0 . …
24.10.7 ( b 2 n 1 ) N 2 n 2 n b 2 n 1 D 2 n k = 1 M 1 k 2 n 1 k b M ( mod M ) ,
16: 19.29 Reduction of General Elliptic Integrals
where the arguments of the R D function are, in order, ( a b ) ( u c ) , ( b c ) ( a u ) , ( a b ) ( b c ) . … The only cases that are integrals of the third kind are those in which at least one m j with j > h is a negative integer and those in which h = 4 and j = 1 n m j is a positive integer. … where …
V = D 12 2 D 11 D 22 .
D 11 = b 1 2 .
17: 19.20 Special Cases
R J ( x , y , z , z ) = R D ( x , y , z ) ,
§19.20(iv) R D ( x , y , z )
R D ( λ x , λ y , λ z ) = λ 3 / 2 R D ( x , y , z ) ,
R D ( 0 , 0 , z ) = .
Define c = j = 1 n b j . …
18: 24.19 Methods of Computation
D 2 n = p 1 | 2 n p ,
B 2 n = N 2 n D 2 n .
  • Tanner and Wagstaff (1987) derives a congruence ( mod p ) for Bernoulli numbers in terms of sums of powers. See also §24.10(iii).

  • Buhler et al. (1992) uses the expansion

    24.19.3 t 2 cosh t 1 = 2 n = 0 ( 2 n 1 ) B 2 n t 2 n ( 2 n ) ! ,

    and computes inverses modulo p of the left-hand side. Multisectioning techniques are applied in implementations. See also Crandall (1996, pp. 116–120).

  • 19: 27.2 Functions
    It can be expressed as a sum over all primes p x : … the sum of the k th powers of the positive integers m n that are relatively prime to n . … It is the special case k = 2 of the function d k ( n ) that counts the number of ways of expressing n as the product of k factors, with the order of factors taken into account. …Note that σ 0 ( n ) = d ( n ) . … Table 27.2.2 tabulates the Euler totient function ϕ ( n ) , the divisor function d ( n ) ( = σ 0 ( n ) ), and the sum of the divisors σ ( n ) ( = σ 1 ( n ) ), for n = 1 ( 1 ) 52 . …
    20: 1.18 Linear Second Order Differential Operators and Eigenfunction Expansions
    Assume that 𝒟 ( T ) is dense in V , i. … u λ 𝒟 ( T ) , corresponding to distinct eigenvalues, are orthogonal: i. … This insures the vanishing of the boundary terms in (1.18.26), and also is a choice which indicates that 𝒟 ( T ) = 𝒟 ( T ) , as f ( x ) and g ( x ) satisfy the same boundary conditions and thus define the same domains. … , 𝒟 ( T ) 𝒟 ( T ) and T v = T v for v 𝒟 ( T ) . … We have a direct sum of linear spaces: 𝒟 ( T ) = 𝒟 ( T ) + N i + N i . …