About the Project

英国旅行签证存款证明〖办证V信ATV1819〗exp

AdvancedHelp

(0.001 seconds)

11—20 of 113 matching pages

11: 5.6 Inequalities
5.6.5 exp ( ( 1 s ) ψ ( x + s 1 / 2 ) ) Γ ( x + 1 ) Γ ( x + s ) exp ( ( 1 s ) ψ ( x + 1 2 ( s + 1 ) ) ) , 0 < s < 1 .
5.6.9 | Γ ( z ) | ( 2 π ) 1 / 2 | z | x ( 1 / 2 ) e π | y | / 2 exp ( 1 6 | z | 1 ) .
12: 4.8 Identities
4.8.10 exp ( ln z ) = exp ( Ln z ) = z .
13: 36.4 Bifurcation Sets
36.4.11 x + i y = z 2 exp ( 2 3 i π m ) , m = 0 , 1 , 2 .
x = 1 12 z 2 ( exp ( 2 τ ) ± 2 exp ( τ ) ) ,
y = 1 12 z 2 ( exp ( 2 τ ) ± 2 exp ( τ ) ) , τ < .
14: 10.14 Inequalities; Monotonicity
10.14.5 | J ν ( ν x ) | x ν exp ( ν ( 1 x 2 ) 1 2 ) ( 1 + ( 1 x 2 ) 1 2 ) ν , ν 0 , 0 < x 1 ;
10.14.6 | J ν ( ν x ) | ( 1 + x 2 ) 1 4 x ( 2 π ν ) 1 2 x ν exp ( ν ( 1 x 2 ) 1 2 ) ( 1 + ( 1 x 2 ) 1 2 ) ν , ν > 0 , 0 < x 1 ;
10.14.8 | J n ( n z ) | | z n exp ( n ( 1 z 2 ) 1 2 ) | | 1 + ( 1 z 2 ) 1 2 | n , n = 0 , 1 , 2 , ,
15: 27.12 Asymptotic Formulas: Primes
27.12.5 | π ( x ) li ( x ) | = O ( x exp ( c ( ln x ) 1 / 2 ) ) , x .
27.12.6 | π ( x ) li ( x ) | = O ( x exp ( d ( ln x ) 3 / 5 ( ln ln x ) 1 / 5 ) ) .
27.12.8 li ( x ) ϕ ( m ) + O ( x exp ( λ ( α ) ( ln x ) 1 / 2 ) ) , m ( ln x ) α , α > 0 ,
16: 36.15 Methods of Computation
Direct numerical evaluation can be carried out along a contour that runs along the segment of the real t -axis containing all real critical points of Φ and is deformed outside this range so as to reach infinity along the asymptotic valleys of exp ( i Φ ) . …
17: 10.56 Generating Functions
10.56.5 exp ( z 2 + 2 i z t ) z = e z z + 2 π n = 1 ( i t ) n n ! 𝗄 n 1 ( z ) .
18: 19.31 Probability Distributions
19.31.2 n ( 𝐱 T 𝐀 𝐱 ) μ exp ( 𝐱 T 𝐁 𝐱 ) d x 1 d x n = π n / 2 Γ ( μ + 1 2 n ) det 𝐁 Γ ( 1 2 n ) R μ ( 1 2 , , 1 2 ; λ 1 , , λ n ) , μ > 1 2 n .
19: 32.14 Combinatorics
32.14.2 F ( s ) = exp ( s ( x s ) w 2 ( x ) d x ) ,
20: 36.9 Integral Identities
36.9.9 | Ψ ( E ) ( x , y , z ) | 2 = 8 π 2 3 2 / 3 0 0 2 π ( Ai ( 1 3 1 / 3 ( x + i y + 2 z u exp ( i θ ) + 3 u 2 exp ( 2 i θ ) ) ) Bi ( 1 3 1 / 3 ( x i y + 2 z u exp ( i θ ) + 3 u 2 exp ( 2 i θ ) ) ) ) u d u d θ .