About the Project

limit circle

AdvancedHelp

(0.001 seconds)

11—20 of 100 matching pages

11: 26.3 Lattice Paths: Binomial Coefficients
§26.3(v) Limiting Form
26.3.12 ( 2 n n ) 4 n π n , n .
12: 4.4 Special Values and Limits
4.4.16 lim z z a e z = 0 , | ph z | 1 2 π δ ( < 1 2 π ),
13: 33.18 Limiting Forms for Large
§33.18 Limiting Forms for Large
14: 10.28 Wronskians and Cross-Products
10.28.1 𝒲 { I ν ( z ) , I ν ( z ) } = I ν ( z ) I ν 1 ( z ) I ν + 1 ( z ) I ν ( z ) = 2 sin ( ν π ) / ( π z ) ,
15: 10.45 Functions of Imaginary Order
K ~ ν ( x ) = ( π / ( 2 x ) ) 1 2 e x ( 1 + O ( x 1 ) ) .
16: 29.5 Special Cases and Limiting Forms
§29.5 Special Cases and Limiting Forms
29.5.4 lim k 1 a ν m ( k 2 ) = lim k 1 b ν m + 1 ( k 2 ) = ν ( ν + 1 ) μ 2 ,
29.5.5 lim k 1 𝐸𝑐 ν m ( z , k 2 ) 𝐸𝑐 ν m ( 0 , k 2 ) = lim k 1 𝐸𝑠 ν m + 1 ( z , k 2 ) 𝐸𝑠 ν m + 1 ( 0 , k 2 ) = 1 ( cosh z ) μ F ( 1 2 μ 1 2 ν , 1 2 μ + 1 2 ν + 1 2 1 2 ; tanh 2 z ) , m even,
lim 𝐸𝑐 ν m ( z , k 2 ) = ce m ( 1 2 π z , θ ) ,
lim 𝐸𝑠 ν m ( z , k 2 ) = se m ( 1 2 π z , θ ) ,
17: 20.5 Infinite Products and Related Results
20.5.14 θ 1 ( z | τ ) = z θ 1 ( 0 | τ ) lim N n = N N lim M m = M | m | + | n | 0 M ( 1 + z ( m + n τ ) π ) ,
20.5.15 θ 2 ( z | τ ) = θ 2 ( 0 | τ ) lim N n = N N lim M m = 1 M M ( 1 + z ( m 1 2 + n τ ) π ) ,
20.5.16 θ 3 ( z | τ ) = θ 3 ( 0 | τ ) lim N n = 1 N N lim M m = 1 M M ( 1 + z ( m 1 2 + ( n 1 2 ) τ ) π ) ,
20.5.17 θ 4 ( z | τ ) = θ 4 ( 0 | τ ) lim N n = 1 N N lim M m = M M ( 1 + z ( m + ( n 1 2 ) τ ) π ) .
18: 1.17 Integral and Series Representations of the Dirac Delta
1.17.6 lim n n π e n ( x a ) 2 ϕ ( x ) d x = ϕ ( a ) ,
1.17.7 lim n n π e n ( x a ) 2 ϕ ( x ) d x = 1 2 ϕ ( a ) + 1 2 ϕ ( a + ) .
1.17.19 lim n π π δ n ( x a ) ϕ ( x ) d x = ϕ ( a ) ,
19: 7.2 Definitions
7.2.1 erf z = 2 π 0 z e t 2 d t ,
lim z erf z = 1 ,
lim z erfc z = 0 , | ph z | 1 4 π δ ( < 1 4 π ) .
lim x C ( x ) = 1 2 ,
lim x S ( x ) = 1 2 .
20: 5.17 Barnes’ G -Function (Double Gamma Function)
5.17.7 C = lim n ( k = 1 n k ln k ( 1 2 n 2 + 1 2 n + 1 12 ) ln n + 1 4 n 2 ) = γ + ln ( 2 π ) 12 ζ ( 2 ) 2 π 2 = 1 12 ζ ( 1 ) ,