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11: 24.15 Related Sequences of Numbers
24.15.7 B n = k = 0 n ( 1 ) k ( n + 1 k + 1 ) S ( n + k , k ) / ( n + k k ) ,
24.15.8 k = 0 n ( 1 ) n + k s ( n + 1 , k + 1 ) B k = n ! n + 1 .
24.15.10 2 n 1 4 n p 2 B 2 n S ( p + 2 n , p 1 ) ( mod p 3 ) , 2 2 n p 3 .
The Fibonacci numbers are defined by u 0 = 0 , u 1 = 1 , and u n + 1 = u n + u n 1 , n 1 . The Lucas numbers are defined by v 0 = 2 , v 1 = 1 , and v n + 1 = v n + v n 1 , n 1 . …
12: Bibliography C
  • B. C. Carlson (1979) Computing elliptic integrals by duplication. Numer. Math. 33 (1), pp. 1–16.
  • B. C. Carlson (1995) Numerical computation of real or complex elliptic integrals. Numer. Algorithms 10 (1-2), pp. 13–26.
  • J. R. Cash and R. V. M. Zahar (1994) A Unified Approach to Recurrence Algorithms. In Approximation and Computation (West Lafayette, IN, 1993), R. V. M. Zahar (Ed.), International Series of Computational Mathematics, Vol. 119, pp. 97–120.
  • H. H. Chan (1998) On Ramanujan’s cubic transformation formula for F 1 2 ( 1 3 , 2 3 ; 1 ; z ) . Math. Proc. Cambridge Philos. Soc. 124 (2), pp. 193–204.
  • Cunningham Project (website)
  • 13: 26.11 Integer Partitions: Compositions
    For example, there are eight compositions of 4: 4 , 3 + 1 , 1 + 3 , 2 + 2 , 2 + 1 + 1 , 1 + 2 + 1 , 1 + 1 + 2 , and 1 + 1 + 1 + 1 . … c ( T , n ) is the number of compositions of n with no 1’s, where again T = { 2 , 3 , 4 , } . …
    F 1 = 1 ,
    F n = F n 1 + F n 2 , n 2 .
    26.11.7 F n = ( 1 + 5 ) n ( 1 5 ) n 2 n 5 .
    14: About MathML
    , built-in to the browser) support for MathML is growing, (see Browsers supporting MathML). …
    Browsers supporting MathML
    The Firefox browser has traditionally had the strongest support for MathML and its native MathML is used by default. Recent enhancements to the WebKit engine now provide support for MathML Core. … Most modern browsers support ‘Web Fonts’, fonts that are effectively included with a web site. …
    15: 24.13 Integrals
    For m , n = 1 , 2 , ,
    24.13.6 0 1 B n ( t ) B m ( t ) d t = ( 1 ) n 1 m ! n ! ( m + n ) ! B m + n .
    24.13.8 0 1 E n ( t ) d t = 2 E n + 1 ( 0 ) n + 1 = 4 ( 2 n + 2 1 ) ( n + 1 ) ( n + 2 ) B n + 2 ,
    For m , n = 1 , 2 , ,
    24.13.11 0 1 E n ( t ) E m ( t ) d t = ( 1 ) n 4 ( 2 m + n + 2 1 ) m ! n ! ( m + n + 2 ) ! B m + n + 2 .
    16: 26.14 Permutations: Order Notation
    The set 𝔖 n 26.13) can be viewed as the collection of all ordered lists of elements of { 1 , 2 , , n } : { σ ( 1 ) σ ( 2 ) σ ( n ) } . …Equivalently, this is the sum over 1 j < n of the number of integers less than σ ( j ) that lie in positions to the right of the j th position: inv ( 35247816 ) = 2 + 3 + 1 + 1 + 2 + 2 + 0 = 11 . It is also equal to the number of permutations in 𝔖 n with exactly k + 1 weak excedances. …
    26.14.5 k = 0 n 1 n k ( x + k n ) = x n .
    26.14.8 n k = ( k + 1 ) n 1 k + ( n k ) n 1 k 1 , n 2 ,
    17: 26.7 Set Partitions: Bell Numbers
    B ( n ) is the number of partitions of { 1 , 2 , , n } . …
    26.7.1 B ( 0 ) = 1 ,
    26.7.4 B ( n ) = e 1 k = 1 k n k ! = 1 + e 1 k = 1 2 n k n k ! .
    26.7.6 B ( n + 1 ) = k = 0 n ( n k ) B ( k ) .
    26.7.7 B ( n ) = N n e N n 1 ( 1 + ln N ) 1 / 2 ( 1 + O ( ( ln n ) 1 / 2 n 1 / 2 ) ) , n ,
    18: 27.14 Unrestricted Partitions
    For example, p ( 5 ) = 7 because there are exactly seven partitions of 5 : 5 = 4 + 1 = 3 + 2 = 3 + 1 + 1 = 2 + 2 + 1 = 2 + 1 + 1 + 1 = 1 + 1 + 1 + 1 + 1 . … with p ( 0 ) = 1 . …where the exponents 1 , 2 , 5 , 7 , 12 , 15 , are the pentagonal numbers, defined by … Logarithmic differentiation of the generating function 1 / f ( x ) leads to another recursion: …where σ 1 ( k ) is defined by (27.2.10) with α = 1 . …
    19: 24.14 Sums
    24.14.4 k = 0 n ( n k ) E k E n k = 2 n + 1 E n + 1 ( 0 ) = 2 n + 2 ( 1 2 n + 2 ) B n + 2 n + 2 .
    24.14.7 j = 0 m k = 0 n ( m j ) ( n k ) B j B k m + n j k + 1 = ( 1 ) m 1 m ! n ! ( m + n ) ! B m + n .
    Let det [ a r + s ] denote a Hankel (or persymmetric) determinant, that is, an ( n + 1 ) × ( n + 1 ) determinant with element a r + s in row r and column s for r , s = 0 , 1 , , n . …
    24.14.11 det [ B r + s ] = ( 1 ) n ( n + 1 ) / 2 ( k = 1 n k ! ) 6 / ( k = 1 2 n + 1 k ! ) ,
    24.14.12 det [ E r + s ] = ( 1 ) n ( n + 1 ) / 2 ( k = 1 n k ! ) 2 .
    20: 27.18 Methods of Computation: Primes
    Two simple algorithms for proving primality require a knowledge of all or part of the factorization of n 1 , n + 1 , or both; see Crandall and Pomerance (2005, §§4.1–4.2). These algorithms are used for testing primality of Mersenne numbers, 2 n 1 , and Fermat numbers, 2 2 n + 1 . …