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宁波驾照是国际驾照【假证加微aptao168】7Bz

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11: Bibliography Q
  • S.-L. Qiu and J.-M. Shen (1997) On two problems concerning means. J. Hangzhou Inst. Elec. Engrg. 17, pp. 1–7 (Chinese).
  • C. K. Qu and R. Wong (1999) “Best possible” upper and lower bounds for the zeros of the Bessel function J ν ( x ) . Trans. Amer. Math. Soc. 351 (7), pp. 2833–2859.
  • 12: Nico M. Temme
  • In November 2015, Temme was named Senior Associate Editor of the DLMF and Associate Editor for Chapters 3, 6, 7, and 12.
    13: 26.9 Integer Partitions: Restricted Number and Part Size
    Table 26.9.1: Partitions p k ( n ) .
    n k
    0 1 2 3 4 5 6 7 8 9 10
    5 0 1 3 5 6 7 7 7 7 7 7
    6 0 1 4 7 9 10 11 11 11 11 11
    7 0 1 4 8 11 13 14 15 15 15 15
    Figure 26.9.1: Ferrers graph of the partition 7 + 4 + 3 + 3 + 2 + 1 .
    14: 32.12 Asymptotic Approximations for Complex Variables
    See Boutroux (1913), Novokshënov (1990), Kapaev (1991), Joshi and Kruskal (1992), Kitaev (1994), Its and Kapaev (2003), and Fokas et al. (2006, Chapter 7). …
    15: 23.23 Tables
    2 in Abramowitz and Stegun (1964) gives values of ( z ) , ( z ) , and ζ ( z ) to 7 or 8D in the rectangular and rhombic cases, normalized so that ω 1 = 1 and ω 3 = i a (rectangular case), or ω 1 = 1 and ω 3 = 1 2 + i a (rhombic case), for a = 1. …
    16: 24.2 Definitions and Generating Functions
    Table 24.2.1: Bernoulli and Euler numbers.
    n B n E n
    14 7 6 1993 60981
    Table 24.2.3: Bernoulli numbers B n = N / D .
    n N D B n
    14 7 6 1.16666 6667
    Table 24.2.5: Coefficients b n , k of the Bernoulli polynomials B n ( x ) = k = 0 n b n , k x k .
    k
    n 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
    7 0 1 6 0 7 6 0 7 2 7 2 1
    Table 24.2.6: Coefficients e n , k of the Euler polynomials E n ( x ) = k = 0 n e n , k x k .
    k
    7 17 8 0 21 2 0 35 4 0 7 2 1
    17: 3.4 Differentiation
    B 3 7 = 1 5040 ( 48 56 t 168 t 2 + 140 t 3 + 35 t 4 42 t 5 + 7 t 6 ) ,
    B 2 7 = 1 720 ( 72 108 t 213 t 2 + 240 t 3 10 t 4 36 t 5 + 7 t 6 ) ,
    B 1 7 = 1 240 ( 144 360 t 48 t 2 + 260 t 3 45 t 4 30 t 5 + 7 t 6 ) ,
    B 0 7 = 1 144 ( 36 + 392 t 147 t 2 224 t 3 + 70 t 4 + 24 t 5 7 t 6 ) ,
    B 1 7 = 1 144 ( 144 + 216 t 264 t 2 156 t 3 + 85 t 4 + 18 t 5 7 t 6 ) ,
    18: 10.73 Physical Applications
    See Jackson (1999, Chapter 3, §§3.7, 3.8, 3.11, 3.13), Lamb (1932, Chapter V, §§100–102; Chapter VIII, §§186, 191–193; Chapter X, §§303, 304), Happel and Brenner (1973, Chapter 3, §3.3; Chapter 7, §7.3), Korenev (2002, Chapter 4, §43), and Gray et al. (1922, Chapter XI). … See Jackson (1999, Chapter 9, §9.6), Jones (1986, Chapters 7, 8), and Lord Rayleigh (1945, Vol. I, Chapter IX, §§200–211, 218, 219, 221a; Vol. II, Chapter XIII, §272a; Chapter XV, §302; Chapter XVIII; Chapter XIX, §350; Chapter XX, §357; Chapter XXI, §369). …See Krivoshlykov (1994, Chapter 2, §2.2.10; Chapter 5, §5.2.2), Kapany and Burke (1972, Chapters 4–6; Chapter 7, §A.1), and Slater (1942, Chapter 4, §§20, 25). … See Smith (1997, Chapter 3, §3.7; Chapter 6, §6.4)Beckmann and Spizzichino (1963, Chapter 4, §§4.2, 4.3; Chapter 5, §§5.2, 5.3; Chapter 6, §6.1; Chapter 7, §7.1.), Kerker (1969, Chapter 5, §5.6.4; Chapter 7, §7.5.6), and Bayvel and Jones (1981, Chapter 1, §§1.6.5, 1.6.6). … See Messiah (1961, Chapter IX, §§7–10). …
    19: 4.9 Continued Fractions
    4.9.1 ln ( 1 + z ) = z 1 + z 2 + z 3 + 4 z 4 + 4 z 5 + 9 z 6 + 9 z 7 + , | ph ( 1 + z ) | < π .
    4.9.2 ln ( 1 + z 1 z ) = 2 z 1 z 2 3 4 z 2 5 9 z 2 7 16 z 2 9 ,
    = 1 + z 1 z 2 + z 3 z 2 + z 5 z 2 + z 7
    20: 7.17 Inverse Error Functions
    7.17.2 inverf x = t + 1 3 t 3 + 7 30 t 5 + 127 630 t 7 + = m = 0 a m t 2 m + 1 , | x | < 1 ,
    7.17.3 inverfc x u 1 / 2 + a 2 u 3 / 2 + a 3 u 5 / 2 + a 4 u 7 / 2 + ,