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19 Elliptic IntegralsLegendre’s Integrals

§19.4 Derivatives and Differential Equations

Contents
  1. §19.4(i) Derivatives
  2. §19.4(ii) Differential Equations

§19.4(i) Derivatives

19.4.1 dK⁡(k)dk =E⁡(k)−k′2⁢K⁡(k)k⁢k′2,
d(E⁡(k)−k′2⁢K⁡(k))dk =k⁢K⁡(k),
19.4.2 dE⁡(k)dk =E⁡(k)−K⁡(k)k,
d(E⁡(k)−K⁡(k))dk =−k⁢E⁡(k)k′2,
19.4.3 d2E⁡(k)dk2=−1k⁢dK⁡(k)dk=k′2⁢K⁡(k)−E⁡(k)k2⁢k′2,
19.4.4 ∂Π⁡(α2,k)∂k=kk′2⁢(k2−α2)⁢(E⁡(k)−k′2⁢Π⁡(α2,k)).
19.4.5 ∂F⁡(ϕ,k)∂k=E⁡(ϕ,k)−k′2⁢F⁡(ϕ,k)k⁢k′2−k⁢sin⁡ϕ⁢cos⁡ϕk′2⁢1−k2⁢sin2⁡ϕ,
19.4.6 ∂E⁡(ϕ,k)∂k=E⁡(ϕ,k)−F⁡(ϕ,k)k,
19.4.7 ∂Π⁡(ϕ,α2,k)∂k=kk′2⁢(k2−α2)⁢(E⁡(ϕ,k)−k′2⁢Π⁡(ϕ,α2,k)−k2⁢sin⁡ϕ⁢cos⁡ϕ1−k2⁢sin2⁡ϕ).

§19.4(ii) Differential Equations

Let Dk=∂/∂k. Then

19.4.8 (k⁢k′2⁢Dk2+(1−3⁢k2)⁢Dk−k)⁢F⁡(ϕ,k)=−k⁢sin⁡ϕ⁢cos⁡ϕ(1−k2⁢sin2⁡ϕ)3/2,
19.4.9 (k⁢k′2⁢Dk2+k′2⁢Dk+k)⁢E⁡(ϕ,k)=k⁢sin⁡ϕ⁢cos⁡ϕ1−k2⁢sin2⁡ϕ.

If ϕ=π/2, then these two equations become hypergeometric differential equations (15.10.1) for K⁡(k) and E⁡(k). An analogous differential equation of third order for Π⁡(ϕ,α2,k) is given in Byrd and Friedman (1971, 118.03).