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11: 12.11 Zeros
Lastly, when a = n 1 2 , n = 1 , 2 , (Hermite polynomial case) U ( a , x ) has n zeros and they lie in the interval [ 2 a , 2 a ] . For further information on these cases see Dean (1966). … Numerical calculations in this case show that z 1 2 , s corresponds to the s th zero on the string; compare §7.13(ii). …
12.11.9 u a , 1 2 1 2 μ ( 1 1.85575 708 μ 4 / 3 0.34438 34 μ 8 / 3 0.16871 5 μ 4 0.11414 μ 16 / 3 0.0808 μ 20 / 3 ) ,