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1: 30.2 Differential Equations
§30.2 Differential Equations
§30.2(i) Spheroidal Differential Equation
The Liouville normal form of equation (30.2.1) is …
§30.2(iii) Special Cases
2: 15.10 Hypergeometric Differential Equation
§15.10 Hypergeometric Differential Equation
§15.10(i) Fundamental Solutions
15.10.1 z ( 1 z ) d 2 w d z 2 + ( c ( a + b + 1 ) z ) d w d z a b w = 0 .
This is the hypergeometric differential equation. …
3: 21.7 Riemann Surfaces
On a Riemann surface of genus g , there are g linearly independent holomorphic differentials ω j , j = 1 , 2 , , g . If a local coordinate z is chosen on the Riemann surface, then the local coordinate representation of these holomorphic differentials is given by …Thus the differentials ω j , j = 1 , 2 , , g have no singularities on Γ . Note that for the purposes of integrating these holomorphic differentials, all cycles on the surface are a linear combination of the cycles a j , b j , j = 1 , 2 , , g . … Define the holomorphic differential
4: 1.9 Calculus of a Complex Variable
u x = v y ,
u y = v x
Conversely, if at a given point ( x , y ) the partial derivatives u / x , u / y , v / x , and v / y exist, are continuous, and satisfy (1.9.25), then f ( z ) is differentiable at z = x + i y .
Analyticity
A function f ( z ) is said to be analytic (holomorphic) at z = z 0 if it is complex differentiable in a neighborhood of z 0 . …
5: 1.5 Calculus of Two or More Variables
The function f ( x , y ) is continuously differentiable if f , f / x , and f / y are continuous, and twice-continuously differentiable if also 2 f / x 2 , 2 f / y 2 , 2 f / x y , and 2 f / y x are continuous. … If F ( x , y ) is continuously differentiable, F ( a , b ) = 0 , and F / y 0 at ( a , b ) , then in a neighborhood of ( a , b ) , that is, an open disk centered at a , b , the equation F ( x , y ) = 0 defines a continuously differentiable function y = g ( x ) such that F ( x , g ( x ) ) = 0 , b = g ( a ) , and g ( x ) = F x / F y . … Sufficient conditions for validity are: (a) f and f / x are continuous on a rectangle a x b , c y d ; (b) when x [ a , b ] both α ( x ) and β ( x ) are continuously differentiable and lie in [ c , d ] . … Suppose that a , b , c are finite, d is finite or + , and f ( x , y ) , f / x are continuous on the partly-closed rectangle or infinite strip [ a , b ] × [ c , d ) . Suppose also that c d f ( x , y ) d y converges and c d ( f / x ) d y converges uniformly on a x b , that is, given any positive number ϵ , however small, we can find a number c 0 [ c , d ) that is independent of x and is such that …
6: 36.10 Differential Equations
§36.10 Differential Equations
K = 2 , cusp: … K = 3 , swallowtail: … In terms of the normal forms (36.2.2) and (36.2.3), the Ψ ( U ) ( 𝐱 ) satisfy the following operator equations …
7: 19.18 Derivatives and Differential Equations
§19.18 Derivatives and Differential Equations
Let j = / z j , and 𝐞 j be an n -tuple with 1 in the j th place and 0’s elsewhere. …
§19.18(ii) Differential Equations
and also a system of n ( n 1 ) / 2 Euler–Poisson differential equations (of which only n 1 are independent): …If n = 2 , then elimination of 2 v between (19.18.11) and (19.18.12), followed by the substitution ( b 1 , b 2 , z 1 , z 2 ) = ( b , c b , 1 z , 1 ) , produces the Gauss hypergeometric equation (15.10.1). …
8: 16.14 Partial Differential Equations
§16.14 Partial Differential Equations
§16.14(i) Appell Functions
x ( 1 x ) 2 F 1 x 2 + y ( 1 x ) 2 F 1 x y + ( γ ( α + β + 1 ) x ) F 1 x β y F 1 y α β F 1 = 0 ,
y ( 1 y ) 2 F 1 y 2 + x ( 1 y ) 2 F 1 x y + ( γ ( α + β + 1 ) y ) F 1 y β x F 1 x α β F 1 = 0 ,
In addition to the four Appell functions there are 24 other sums of double series that cannot be expressed as a product of two F 1 2 functions, and which satisfy pairs of linear partial differential equations of the second order. …
9: 4.10 Integrals
4.10.1 d z z = ln z ,
4.10.2 ln z d z = z ln z z ,
4.10.4 d z z ln z = ln ( ln z ) ,
4.10.5 0 1 ln t 1 t d t = π 2 6 ,
4.10.6 0 1 ln t 1 + t d t = π 2 12 ,
10: 10.38 Derivatives with Respect to Order
For I ν ( z ) / ν at ν = n combine (10.38.1), (10.38.2), and (10.38.4).
10.38.4 K ν ( z ) ν | ν = n = n ! 2 ( 1 2 z ) n k = 0 n 1 ( 1 2 z ) k K k ( z ) k ! ( n k ) .
I ν ( z ) ν | ν = 0 = K 0 ( z ) ,
K ν ( z ) ν | ν = 0 = 0 .