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1: 10.59 Integrals
2: 23.18 Modular Transformations
Here e and o are generic symbols for even and odd integers, respectively. In particular, if a 1 , b , c , and d 1 are all even, then …
3: 27.13 Functions
Every even integer n > 4 is the sum of two odd primes. In this case, S ( n ) is the number of solutions of the equation n = p + q , where p and q are odd primes. Goldbach’s assertion is that S ( n ) 1 for all even n > 4 . …Vinogradov (1937) proves that every sufficiently large odd integer is the sum of three odd primes, and Chen (1966) shows that every sufficiently large even integer is the sum of a prime and a number with no more than two prime factors. … By similar methods Jacobi proved that r 4 ( n ) = 8 σ 1 ( n ) if n is odd, whereas, if n is even, r 4 ( n ) = 24 times the sum of the odd divisors of n . …Exact formulas for r k ( n ) have also been found for k = 3 , 5 , and 7 , and for all even k 24 . …
4: 29.12 Definitions
Table 29.12.1: Lamé polynomials.
ν
eigenvalue
h
eigenfunction
w ( z )
polynomial
form
real
period
imag.
period
parity of
w ( z )
parity of
w ( z K )
parity of
w ( z K i K )
2 n + 1 a ν 2 m + 1 ( k 2 ) 𝑠𝐸 ν m ( z , k 2 ) sn P ( sn 2 ) 4 K 2 i K odd even even
2 n + 1 b ν 2 m + 1 ( k 2 ) 𝑐𝐸 ν m ( z , k 2 ) cn P ( sn 2 ) 4 K 4 i K even odd even
2 n + 2 b ν 2 m + 2 ( k 2 ) 𝑠𝑐𝐸 ν m ( z , k 2 ) sn cn P ( sn 2 ) 2 K 4 i K odd odd even
2 n + 2 a ν 2 m + 1 ( k 2 ) 𝑠𝑑𝐸 ν m ( z , k 2 ) sn dn P ( sn 2 ) 4 K 4 i K odd even odd
2 n + 2 b ν 2 m + 1 ( k 2 ) 𝑐𝑑𝐸 ν m ( z , k 2 ) cn dn P ( sn 2 ) 4 K 2 i K even odd odd
5: 26.13 Permutations: Cycle Notation
For the example (26.13.2), this decomposition is given by ( 1 , 3 , 2 , 5 , 7 ) ( 6 , 8 ) = ( 1 , 3 ) ( 2 , 3 ) ( 2 , 5 ) ( 5 , 7 ) ( 6 , 8 ) . A permutation is even or odd according to the parity of the number of transpositions. The sign of a permutation is + if the permutation is even, if it is odd. …
6: 24.11 Asymptotic Approximations
24.11.5 ( 1 ) n / 2 1 ( 2 π ) n 2 ( n ! ) B n ( x ) { cos ( 2 π x ) , n  even , sin ( 2 π x ) , n  odd ,
24.11.6 ( 1 ) ( n + 1 ) / 2 π n + 1 4 ( n ! ) E n ( x ) { sin ( π x ) , n  even , cos ( π x ) , n  odd ,
7: 14.16 Zeros
  • (c)

    μ > 0 , n < m , and m n is odd.

  • (b)

    μ > 0 , n < m , and m n is even.

  • 𝖰 ν μ ( x ) has max ( ν | μ | , 0 ) + k zeros in the interval ( 1 , 1 ) , where k can take one of the values 1 , 0 , 1 , 2 , subject to max ( ν | μ | , 0 ) + k being even or odd according as cos ( ν π ) and cos ( μ π ) have opposite signs or the same sign. …
  • (b)

    μ ν , μ , and μ is odd.

  • 8: 24.12 Zeros
    When n ( 2 ) is evenWhen n is odd x 1 ( n ) = 1 2 , x 2 ( n ) = 1 ( n 3 ) , and as n with m ( 1 ) fixed, … When n ( 2 ) is even y 1 ( n ) = 1 , and as n with m ( 1 ) fixed, … When n is odd y 1 ( n ) = 1 2 , … The only polynomial E n ( x ) with multiple zeros is E 5 ( x ) = ( x 1 2 ) ( x 2 x 1 ) 2 .
    9: 30.4 Functions of the First Kind
    the sign of 𝖯𝗌 n m ( 0 , γ 2 ) being ( 1 ) ( n + m ) / 2 when n m is even, and the sign of d 𝖯𝗌 n m ( x , γ 2 ) / d x | x = 0 being ( 1 ) ( n + m 1 ) / 2 when n m is odd. … with α k , β k , γ k from (30.3.6), and g 1 = g 2 = 0 , g k = 0 for even k if n m is odd and g k = 0 for odd k if n m is even. …
    10: 30.16 Methods of Computation
    Let n m be even. … If n m is odd, then (30.16.1) is replaced by … If λ n m ( γ 2 ) is known, then we can compute 𝖯𝗌 n m ( x , γ 2 ) (not normalized) by solving the differential equation (30.2.1) numerically with initial conditions w ( 0 ) = 1 , w ( 0 ) = 0 if n m is even, or w ( 0 ) = 0 , w ( 0 ) = 1 if n m is odd. … Let 𝐀 be the d × d matrix given by (30.16.1) if n m is even, or by (30.16.6) if n m is odd. …