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1: 22.17 Moduli Outside the Interval [0,1]
§22.17 Moduli Outside the Interval [0,1]
k 1 = k 1 + k 2 ,
k 1 k 1 = k 1 + k 2 ,
22.17.7 cn ( z , i k ) = cd ( z / k 1 , k 1 ) ,
For proofs of these results and further information see Walker (2003).
2: 22.7 Landen Transformations
22.7.1 k 1 = 1 k 1 + k ,
k 2 = 2 k 1 + k ,
k 2 = 1 k 1 + k ,
22.7.6 sn ( z , k ) = ( 1 + k 2 ) sn ( z / ( 1 + k 2 ) , k 2 ) cn ( z / ( 1 + k 2 ) , k 2 ) dn ( z / ( 1 + k 2 ) , k 2 ) ,
22.7.8 dn ( z , k ) = ( 1 k 2 ) ( dn 2 ( z / ( 1 + k 2 ) , k 2 ) + k 2 ) k 2 2 dn ( z / ( 1 + k 2 ) , k 2 ) .
3: Sidebar 5.SB1: Gamma & Digamma Phase Plots
In the upper half of the image, the poles of Γ ( z ) are clearly visible at negative integer values of z : the phase changes by 2 π around each pole, showing a full revolution of the color wheel. … Phase changes around the zeros are of opposite sign to those around the poles. …
4: 19.7 Connection Formulas
§19.7(ii) Change of Modulus and Amplitude
κ = k 1 + k 2 ,
κ = 1 1 + k 2 ,
With sinh ϕ = tan ψ , …
§19.7(iii) Change of Parameter of Π ( ϕ , α 2 , k )
5: 19.8 Quadratic Transformations
k 1 = 1 k 1 + k ,
c 1 = csc 2 ϕ 1 .
k 2 = 2 k / ( 1 + k ) ,
k 1 = ( 1 k ) / ( 1 + k ) ,
c = csc 2 ϕ .
6: 7.16 Generalized Error Functions
These functions can be expressed in terms of the incomplete gamma function γ ( a , z ) 8.2(i)) by change of integration variable.
7: 27 Functions of Number Theory
8: 23.21 Physical Applications
Another form is obtained by identifying e 1 , e 2 , e 3 as lattice roots (§23.3(i)), and setting …
23.21.5 ( ( v ) ( w ) ) ( ( w ) ( u ) ) ( ( u ) ( v ) ) 2 = ( ( w ) ( v ) ) 2 u 2 + ( ( u ) ( w ) ) 2 v 2 + ( ( v ) ( u ) ) 2 w 2 .
9: Foreword
Much has changed in the years since A&S was published. …However, we have also seen the birth of a new age of computing technology, which has not only changed how we utilize special functions, but also how we communicate technical information. …
10: 22.11 Fourier and Hyperbolic Series
22.11.1 sn ( z , k ) = 2 π K k n = 0 q n + 1 2 sin ( ( 2 n + 1 ) ζ ) 1 q 2 n + 1 ,
22.11.2 cn ( z , k ) = 2 π K k n = 0 q n + 1 2 cos ( ( 2 n + 1 ) ζ ) 1 + q 2 n + 1 ,
22.11.3 dn ( z , k ) = π 2 K + 2 π K n = 1 q n cos ( 2 n ζ ) 1 + q 2 n .
22.11.4 cd ( z , k ) = 2 π K k n = 0 ( 1 ) n q n + 1 2 cos ( ( 2 n + 1 ) ζ ) 1 q 2 n + 1 ,
22.11.5 sd ( z , k ) = 2 π K k k n = 0 ( 1 ) n q n + 1 2 sin ( ( 2 n + 1 ) ζ ) 1 + q 2 n + 1 ,