Ai′⁡z=-π-1⁢z/3⁢K±2/3⁡ζ=z/3⁢I2/3⁡ζ-I-2/3⁡ζ=12⁢z/3⁢ⅇ-π⁢ⅈ/6⁢H2/31⁡ζ⁢ⅇπ⁢ⅈ/2=12⁢z/3⁢ⅇ-5⁢π⁢ⅈ/6⁢H-2/31⁡ζ⁢ⅇπ⁢ⅈ/2=12⁢z/3⁢ⅇπ⁢ⅈ/6⁢H2/32⁡ζ⁢ⅇ-π⁢ⅈ/2=12⁢z/3⁢ⅇ5⁢π⁢ⅈ/6⁢H-2/32⁡ζ⁢ⅇ-π⁢ⅈ/2,