Bi(z)=z/3(I1/3(ζ)+I1/3(ζ))=12z/3(eπi/6H1/3(1)(ζeπi/2)+eπi/6H1/3(2)(ζeπi/2))=12z/3(eπi/6H1/3(1)(ζeπi/2)+eπi/6H1/3(2)(ζeπi/2)),