Ai′⁡(z)=-π-1⁢(z/3)⁢K±2/3⁡(ζ)=(z/3)⁢(I2/3⁡(ζ)-I-2/3⁡(ζ))=12⁢(z/3)⁢ⅇ-π⁢ⅈ/6⁢H2/3(1)⁡(ζ⁢ⅇπ⁢ⅈ/2)=12⁢(z/3)⁢ⅇ-5⁢π⁢ⅈ/6⁢H-2/3(1)⁡(ζ⁢ⅇπ⁢ⅈ/2)=12⁢(z/3)⁢ⅇπ⁢ⅈ/6⁢H2/3(2)⁡(ζ⁢ⅇ-π⁢ⅈ/2)=12⁢(z/3)⁢ⅇ5⁢π⁢ⅈ/6⁢H-2/3(2)⁡(ζ⁢ⅇ-π⁢ⅈ/2),