H1/3(2)⁡(ζ)=ⅇπ⁢ⅈ/3⁢H-1/3(2)⁡(ζ)=ⅇπ⁢ⅈ/6⁢3/z⁢(Ai⁡(-z)+ⅈ⁢Bi⁡(-z)),