H1/3(1)⁡(ζ)=ⅇ-π⁢ⅈ/3⁢H-1/3(1)⁡(ζ)=ⅇ-π⁢ⅈ/6⁢3/z⁢(Ai⁡(-z)-ⅈ⁢Bi⁡(-z)),