1(2⁢π)n/2⁢∫(-∞,∞)n|Δ⁡(t1,…,tn)|2⁢c⁢∏k=1nexp⁡(-12⁢tk2)⁢ⅆ⁡tk=∏k=1nΓ⁡(1+k⁢c)(Γ⁡(1+c))n,