πB(r,r,r)π cyclically symmetricq|π|=h=1r1-q3h-11-q3h-21h<jr1-q3(h+2j-1)1-q3(h+j-1)=h=1r(1-q3h-11-q3h-2j=hr1-q3(r+h+j-1)1-q3(2h+j-1)).