(-1)kζ(k)(s,a)=(lna)kas(12+as-1)+k!a1-sr=0k-1(lna)rr!(s-1)k-r+1-s(s+1)0B~2(x)(ln(x+a))k(x+a)s+2x+k(2s+1)0B~2(x)(ln(x+a))k-1(x+a)s+2x-k(k-1)0B~2(x)(ln(x+a))k-2(x+a)s+2x,