d1,4(2)⁢d2,4(2)⁢d3,4(2)±d2,4(2)⁢d3,4(2)⁢d4,4(2)+d3,4(2)⁢d4,4(2)⁢d1,4(2)±d4,4(2)⁢d1,4(2)⁢d2,4(2)=k′⁢(±d1,4(2)+d2,4(2)±d3,4(2)+d4,4(2)),