These theorems reduce integrals over a real interval
of certain
integrands containing the square root of a quartic or cubic polynomial to
symmetric integrals over
containing the square root of a cubic
polynomial (compare §19.16(i)). Let
and assume that the line segment with endpoints
and
lies in
for
. If
and
is any permutation of the numbers
, then
where
There are only three distinct
’s with subscripts
, and at most one
of them can be 0 because the
’s are nonzero. Then
where
The Cauchy principal value is taken when
or
is real and negative. Cubic cases of these formulas are obtained by setting
one of the factors in (19.29.3) equal to 1.
The advantages of symmetric integrals for tables of integrals and symbolic
integration are illustrated by (19.29.4) and its cubic case, which
replace the
formulas in
Gradshteyn and Ryzhik (2000, 3.147, 3.131, 3.152) after taking
as the
variable of integration in 3.152. Moreover, the requirement that one limit of
integration be a branch point of the integrand is eliminated without doubling
the number of standard integrals in the result. (19.29.7) subsumes all
72 formulas in Gradshteyn and Ryzhik (2000, 3.168), and its cubic cases
similarly replace the
formulas in
Gradshteyn and Ryzhik (2000, 3.133, 3.142, and 3.141(1-18)). For example,
3.142(2) is included as

where the arguments of the
function are, in order,
,
,
.
(19.2.3) can be written
where
,
or 4,
, and
is an integer. Define
where
is an
-tuple with 1 in the
th position and 0’s
elsewhere. Define also
and retain the notation and
conditions associated with (19.29.1) and (19.29.2). The
integrals in (19.29.4), (19.29.7), and (19.29.8)
are
,
, and
, respectively.
The only cases of
that are integrals of the first kind
are the two (
or 4) with
. The only cases that
are integrals of the third kind are those in which at least one
with
is a negative integer and those in which
and
is a positive integer. All other cases are integrals of the
second kind.
can be reduced to a linear combination of basic
integrals and algebraic functions. In the cubic case (
) the basic
integrals are
In the quartic case (
) the basic integrals are
Basic integrals of type
,
, are not linearly
independent, nor are those of type
,
.
The reduction of
is carried out by a relation derived from
partial fractions and by use of two recurrence relations. These are given in
Carlson (1999, (2.19), (3.5), (3.11)) and simplified in
Carlson (2002, (1.10), (1.7), (1.8)) by means of modified
definitions. Partial fractions provide a reduction to integrals in which
has at most one nonzero component, and these are then reduced to
basic integrals by the recurrence relations. A special case of
Carlson (1999, (2.19)) is given by
which shows how to express the basic integral
in terms of
symmetric integrals by using (19.29.4) and either (19.29.7)
or (19.29.8). The first choice gives a formula that includes the
18+9+18 = 45 formulas in Gradshteyn and Ryzhik (2000, 3.133, 3.156, 3.158), and
the second choice includes the 8+8+8+12 = 36 formulas in
Gradshteyn and Ryzhik (2000, 3.151, 3.149, 3.137, 3.157) (after setting
in some cases).
If
, then the recurrence relation (Carlson (1999, (3.5))) has
the special case
where
is any permutation of the numbers
, and
(This shows why
is not needed as a basic integral in the
cubic case.) In the quartic case this recurrence relation has an extra term in
, and hence
,
, is a basic integral. It can be expressed in terms of
symmetric integrals by setting
and
in (19.29.8).
The other recurrence relation is

see Carlson (1999, (3.11)). An example that uses (19.29.15)–(19.29.18) is given in §19.34.
For an implementation by James FitzSimons of the method for reducing
to basic integrals and extensive tables of such reductions,
see Carlson (1999) and Carlson and FitzSimons (2000).
Another method of reduction is given in Gray (2002). It depends primarily on multivariate recurrence relations that replace one integral by two or more.
The first formula replaces (19.14.4)–(19.14.10). Define
,
and assume both
’s are positive for
. Then
and
where
If both square roots in (19.29.22) are 0, then the indeterminacy in
the two preceding equations can be removed by using (19.27.8) to
evaluate the integral as
multiplied either by
or by
in the cases of (19.29.20) or
(19.29.21), respectively. If
, then
is found by
taking the limit. For example,
Next, for
, define
, and assume both
’s
are positive for
. If each has real zeros, then (19.29.4)
may be simpler than
where
(The variables of
are real and nonnegative unless both
’s have
real zeros and those of
interlace those of
.) If
, where both linear factors are positive
for
, and
, then
(19.29.25) is modified so that
with other quantities remaining as in (19.29.25). In the cubic case,
in which
,
, (19.29.26) reduces further to
For example, because
, we find that when
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where
Lastly, define
and assume
is positive and
monotonic for
. Then
where
For example, if
and
, then
where