∫0π/2RF⁡(sin2⁡θ⁢cos2⁡(x+y),sin2⁡θ⁢cos2⁡(x-y),1)⁢ⅆ⁡θ=RF⁡(0,cos2⁡x,1)⁢RF⁡(0,cos2⁡y,1),