∫0∞ⅇ-x2⁢He2⁢n+1⁡(2⁢x)⁢sin⁡(x⁢y)⁢ⅆ⁡x=(-1)n⁢12⁢π⁢ⅇ-14⁢y2⁢He2⁢n+1⁡(y).