∫0∞ⅇ-12⁢x2⁢He2⁢n+1⁡(x)⁢sin⁡(x⁢y)⁢ⅆ⁡x=(-1)n⁢12⁢π⁢y2⁢n+1⁢ⅇ-12⁢y2,