∫01(1-x2)λ-12⁢C2⁢n+1(λ)⁡(x)⁢sin⁡(x⁢y)⁢ⅆ⁡x=(-1)n⁢π⁢Γ⁡(2⁢n+2⁢λ+1)⁢J2⁢n+λ+1⁡(y)(2⁢n+1)!⁢Γ⁡(λ)⁢(2⁢y)λ.