(12⁢(1-x)⁢z)-12⁢α⁢Jα⁡(2⁢(1-x)⁢z)⁢(12⁢(1+x)⁢z)-12⁢β⁢Iβ⁡(2⁢(1+x)⁢z)=∑n=0∞Pn(α,β)⁡(x)Γ⁡(n+α+1)⁢Γ⁡(n+β+1)⁢zn.