Fqq+1⁡(a1,…,aq+1b1,…,bq;z)=∑j=1q+1(∏k=1k≠jq+1Γ⁡(ak-aj)Γ⁡(ak)/∏k=1qΓ⁡(bk-aj)Γ⁡(bk))⁢w~j⁢(z),