Fpp+1⁡(a1+r,…,ak-1+r,ak,…,ap+1b1+r,…,bk+r,bk+1,…,bp;z)=∑n=0m-1(a1+r)n⁢⋯⁢(ak-1+r)n⁢(ak)n⁢⋯⁢(ap+1)n(b1+r)n⁢⋯⁢(bk+r)n⁢(bk+1)n⁢⋯⁢(bp)n⁢znn!+O⁡(1rm),