F(a,ba+b+m;z)=1Γ(a+m)Γ(b+m)k=0m-1(a)k(b)k(m-k-1)!k!(z-1)k-(z-1)mΓ(a)Γ(b)k=0(a+m)k(b+m)kk!(k+m)!(1-z)k(ln(1-z)-ψ(k+1)-ψ(k+m+1)+ψ(a+k+m)+ψ(b+k+m)),