((1-z)⁢ⅆⅆ⁡z⁡(1-z))n⁢((1-z)a-1⁢F⁡(a,b;c;z))=(-1)n⁢(a)n⁢(c-b)n(c)n⁢(1-z)a+n-1⁢F⁡(a+n,b;c+n;z).