F(-m,bn;z)lnz-k=1n-1(n-1)!(k-1)!(n-k-1)!(m+1)k(1-b)k(-z)-k+k=0m(-m)k(b)k(n)kk!zk(ψ(1+m-k)+ψ(b+k)-ψ(1+k)-ψ(n+k))+(-1)mm!k=m+1(k-1-m)!(b)k(n)kk!zk,