w3⁢(z)=ⅇ-a⁢π⁢ⅈ⁢Γ⁡(a+b-c+1)⁢Γ⁡(b-a)Γ⁡(b)⁢Γ⁡(b-c+1)⁢w5⁢(z)+ⅇ-b⁢π⁢ⅈ⁢Γ⁡(a+b-c+1)⁢Γ⁡(a-b)Γ⁡(a)⁢Γ⁡(a-c+1)⁢w6⁢(z),