Mκ,μ⁡(z)⁢Mκ,-μ-1⁡(z)+(12+μ+κ)⁢(12+μ-κ)4⁢μ⁢(1+μ)⁢(1+2⁢μ)2⁢Mκ,μ+1⁡(z)⁢Mκ,-μ⁡(z)=1.