lim2⁢μ→-n-1⁡Mκ,μ⁡(z)Γ⁡(2⁢μ+1)=(-12⁢n-κ)n+1(n+1)!⁢Mκ,12⁢(n+1)⁡(z)=ⅇ-12⁢z⁢z-12⁢n⁢∑s=n+1∞(-12⁢n-κ)sΓ⁡(s-n)⁢s!⁢zs.