Kn⁡(z)=n!⁢(12⁢z)-n2⁢∑k=0n-1(-1)k⁢(12⁢z)k⁢Ik⁡(z)k!⁢(n-k)+(-1)n-1⁢(ln⁡(12⁢z)-ψ⁡(n+1))⁢In⁡(z)+(-1)n⁢∑k=1∞(n+2⁢k)⁢In+2⁢k⁡(z)k⁢(n+k),