ⅇz⁢sin⁡θ=I0⁡(z)+2⁢∑k=0∞(-1)k⁢I2⁢k+1⁡(z)⁢sin⁡((2⁢k+1)⁢θ)+2⁢∑k=1∞(-1)k⁢I2⁢k⁡(z)⁢cos⁡(2⁢k⁢θ).