b0+a1b1+a2b2+a3b3+⋯=b0+a1/b11+a2/(b1⁢b2)1+a3/(b2⁢b3)1+⋯an/(bn-1⁢bn)1+⋯=b0+1(1/a1)⁢b1+1(a1/a2)⁢b2+1(a2/(a1⁢a3))⁢b3+1(a1⁢a3/(a2⁢a4))⁢b4+⋯.